IndiaBIX

Aptitude - Logarithm - Discussion

Discussion Forum : Logarithm - General Questions (Q.No. 2)
Logarithm
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
2.870
2.967
3.876
3.912
Answer: Option
Explanation:
log5 512
= log 512
log 5
= log 29
log (10/2)
= 9 log 2
log 10 - log 2
= (9 x 0.3010)
1 - 0.3010
= 2.709
0.699
= 2709
699
= 3.876
Discussion:
71 comments Page 4 of 8.
Harshini said:   6 years ago
Why should we take log 5 only?
Stella said:   5 years ago
Hi, I am confused about the second step please help me and explain more.
Habibur Rahman said:   5 years ago
Anyone explain it easily.
Sriya said:   5 years ago
I am not getting this, Can anyone explain in correct way?
Devilyne ras said:   5 years ago
Please try to explain in statement.
Priya said:   5 years ago
Please anyone explain. Please.
Jeromy said:   1 decade ago
Why are they dividing log 512 by log 5?
Saurabh said:   1 decade ago
Why are they dividing log 512 by log 5?
Raj kumar said:   1 decade ago
@Nirav.

log512/log5 = 9log2/log(2+3) = 9log2/(log2*log3).

= 9*.3010/(.3010*.4771).

= 9/.4771 >18.
Nagdish kewat said:   1 decade ago
What is the answer of log3(log2(log3t)) =1 t=?
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers