Aptitude - Logarithm - Discussion

Discussion Forum : Logarithm - General Questions (Q.No. 2)
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
2.870
2.967
3.876
3.912
Answer: Option
Explanation:
log5 512
= log 512
log 5
= log 29
log (10/2)
= 9 log 2
log 10 - log 2
= (9 x 0.3010)
1 - 0.3010
= 2.709
0.699
= 2709
699
= 3.876
Discussion:
71 comments Page 3 of 8.

Vaishu said:   1 decade ago
If log 2 10 = 0.3010 and log 7 10 = 0.8451, then the value of log 2.8?

Kennedy said:   9 years ago
Please explain the last part are you supposed to divide or subtract?

Ayesha said:   8 years ago
If log2=0.3010 then find the value of log32. Can someone solve this?

Kate said:   1 decade ago
Please I don't know anything about math I need help forms you guys.

Sandy said:   1 decade ago
log 10 means
log 10 to the base 10
that ts equal to 1
so,
log10=1

Pavan s@i said:   9 years ago
How to write log 4 power 2013, if log 2 = 0.3010? Please help me.

Aman mittal said:   7 years ago
Log base is 5 and exponential is 512 so how you kept log5=log512?
(1)

Vipin Mishra said:   1 decade ago
Formula:

log a x = log x/log a.

log 5 512 = log 512/log 5.

AMAN SRIVASTAVA said:   9 years ago
Which property of log is used in:- log5 512 = log 512/log 5.

Angel said:   8 years ago
Given that log 2 =0.3010 and log 3=0.4771 what is log 1.125?
(1)


Post your comments here:

Your comments will be displayed after verification.