Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 2)
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
Answer: Option
Explanation:
| log5 512 |
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| = 3.876 |
Discussion:
71 comments Page 2 of 8.
Michael Essandoh said:
9 years ago
Please solve this, given that log 9 = 0.9542 and log 6 = 0.7781, find the value of log base 10 of 225.
Shreyash said:
9 years ago
@Arban.
Whenever base is not mentioned, it is taken as 10.
So, log 10 =1 (as the base here is 10).
Whenever base is not mentioned, it is taken as 10.
So, log 10 =1 (as the base here is 10).
Koala said:
9 years ago
It is a basic formula of logarithm.
If,
log(a/b) = log a - log b
log (a.b) = log a + log b
If,
log(a/b) = log a - log b
log (a.b) = log a + log b
Akash said:
9 years ago
If log (a + b)/7 = loga + logb/2 then show that a/b + b/a = 47. Can anyone solve this problem?
Ankush premi said:
8 years ago
How to solve this question 1-log5= 1/3 ( log1/2+logx +1/3 log5)?
Can anyone solve this
Can anyone solve this
Kasthuri said:
1 decade ago
If log 2 = 0.3010 and log 3 = 0.4771,and log 7 = 0.8451 then the value of log75 is?
Dinesh puri said:
8 years ago
When log3=0.4771 and log 5=0.690then find value of log 4=?
Please solve this.
Please solve this.
Shakti said:
6 years ago
Sir is there any methods to solve 2709/699.
It is complicated to solve soo.
It is complicated to solve soo.
Sumeet said:
1 decade ago
If log(10/2) = log5, then log(512/5) should be equal to log(9/1). Isn't it?
Stella said:
5 years ago
Hi, I am confused about the second step please help me and explain more.
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