Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 2)
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
Answer: Option
Explanation:
| log5 512 |
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| = 3.876 |
Discussion:
71 comments Page 3 of 8.
MANASA said:
8 years ago
Superb explanation, Thank you all.
Siddharth said:
8 years ago
@Ayesha.
log32 = log(2^5)= 5log2=5*0.3010= 1.505.
log32 = log(2^5)= 5log2=5*0.3010= 1.505.
Ayesha said:
8 years ago
If log2=0.3010 then find the value of log32. Can someone solve this?
Mushariq said:
9 years ago
Nice explanation, thank you for all your solution.
Mansi said:
9 years ago
Here Log2 =0.3010.
Then, Find log 5.
Then, Find log 5.
Shreyash said:
9 years ago
@Arban.
Whenever base is not mentioned, it is taken as 10.
So, log 10 =1 (as the base here is 10).
Whenever base is not mentioned, it is taken as 10.
So, log 10 =1 (as the base here is 10).
Anu said:
9 years ago
How to subtract 1 - 0.3010 =? Explain.
Saffee2 said:
9 years ago
@Michael Essandoh.
Is it 2.5104?
Is it 2.5104?
Michael Essandoh said:
9 years ago
Please solve this, given that log 9 = 0.9542 and log 6 = 0.7781, find the value of log base 10 of 225.
ArBan said:
9 years ago
How can log 10 be 1? It can only be 1 if the base is 10. If I remember the formula correctly then the base can be anything and is generally a random constant term (a, b etc. ). If we follow the same logic then the answer is most definitely wrong as per my calculations.
CAN ANYONE EXPLAIN THE CORRECT PROCESS?
CAN ANYONE EXPLAIN THE CORRECT PROCESS?
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