Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 2)
2.
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
Answer: Option
Explanation:
| log5 512 |
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| = 3.876 |
Discussion:
71 comments Page 2 of 8.
Amrita said:
6 years ago
Can log 5 be written as log 2 + log 3?
(1)
Srini said:
6 years ago
How did you get 0.3010? please, do explain.
Simran said:
7 years ago
Can anyone explain it properly?
Aman mittal said:
7 years ago
Log base is 5 and exponential is 512 so how you kept log5=log512?
(1)
Sweta said:
7 years ago
@Dinesh Puri.
log 4=log 2^2.
=2log2,
=2log(10/5),
= 2*{log10-log5},
= 2*{1-.690},
= 0.62.
log 4=log 2^2.
=2log2,
=2log(10/5),
= 2*{log10-log5},
= 2*{1-.690},
= 0.62.
Dinesh puri said:
8 years ago
When log3=0.4771 and log 5=0.690then find value of log 4=?
Please solve this.
Please solve this.
Angel said:
8 years ago
Given that log 2 =0.3010 and log 3=0.4771 what is log 1.125?
(1)
Bittu said:
8 years ago
Why do we take log base 10 in log table?
Ankush premi said:
8 years ago
How to solve this question 1-log5= 1/3 ( log1/2+logx +1/3 log5)?
Can anyone solve this
Can anyone solve this
Dheeraj said:
8 years ago
@Naveen.
log27=log3^3=3log3=3 * 0.4771=1.4313.
log27=log3^3=3log3=3 * 0.4771=1.4313.
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