Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 4)
4.
If log 27 = 1.431, then the value of log 9 is:
Answer: Option
Explanation:
log 27 = 1.431
log (33 ) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.
Discussion:
14 comments Page 2 of 2.
Anouska said:
8 years ago
Thanks for the solution. It helped a lot.
Shubhek k.r said:
7 years ago
How find value of log3 =0.477? Please explain it.
(6)
Rohish Zade said:
5 years ago
Log 9 = log(27/3).
= Log 27 - log 3.
= 1.431 - 0.4771 // log 3 = 0.4771,
= 0.954.
= Log 27 - log 3.
= 1.431 - 0.4771 // log 3 = 0.4771,
= 0.954.
(3)
CHHOTU SHAW said:
9 months ago
log27 = 1.431
log3^3 = 1.431
3 log 3 = 1.431
log 3 = 1.431/3
log 3 = 0.477
Find log 9.
log 3^2.
2log 3 and the value of log3 is 0.477.
2 * 0.477 = 0.954.
log3^3 = 1.431
3 log 3 = 1.431
log 3 = 1.431/3
log 3 = 0.477
Find log 9.
log 3^2.
2log 3 and the value of log3 is 0.477.
2 * 0.477 = 0.954.
(1)
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