Aptitude - Logarithm - Discussion

Discussion Forum : Logarithm - General Questions (Q.No. 4)
4.
If log 27 = 1.431, then the value of log 9 is:
0.934
0.945
0.954
0.958
Answer: Option
Explanation:

log 27 = 1.431

log (33 ) = 1.431

3 log 3 = 1.431

log 3 = 0.477

log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.

Discussion:
14 comments Page 1 of 2.

Shubhek k.r said:   7 years ago
How find value of log3 =0.477? Please explain it.
(6)

Rohish Zade said:   5 years ago
Log 9 = log(27/3).
= Log 27 - log 3.
= 1.431 - 0.4771 // log 3 = 0.4771,
= 0.954.
(3)

Maria said:   1 decade ago
Please tell me how we can divide the value with the point I don't know how to divide with a point value like 3.
(1)

CHHOTU SHAW said:   9 months ago
log27 = 1.431
log3^3 = 1.431
3 log 3 = 1.431
log 3 = 1.431/3
log 3 = 0.477

Find log 9.
log 3^2.
2log 3 and the value of log3 is 0.477.
2 * 0.477 = 0.954.
(1)

Arvind said:   1 decade ago
How come log3 value .477

Olamikan adesanmi said:   1 decade ago
You divide 1. 431 by 3, making log3 subject of formula you get log 3 = 0.477

Subham singh rathore said:   1 decade ago
log27=1.431
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log9=log3^2 then
2log3
2*0.477 = 0.954

Hanumanth said:   1 decade ago
log27=1.431
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log(9*3)=1.431
log9+log3=1.431
log9=1.431-0.477
log9=0.954

Jilpy said:   1 decade ago
@Arvind.

Here, 3* log3 = 1.431.

Then,
1.431/3 = 0.477.

Mr. Bean said:   1 decade ago
log27 = log(3*9) = log3+log9.

So, log9 = log27-log3.
log9 = 1.4310-0.4771.
log9 = 0.9539 ~ 0.954.


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