Aptitude - Logarithm - Discussion
Discussion Forum : Logarithm - General Questions (Q.No. 4)
4.
If log 27 = 1.431, then the value of log 9 is:
Answer: Option
Explanation:
log 27 = 1.431
log (33 ) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.
Discussion:
14 comments Page 2 of 2.
Hanumanth said:
1 decade ago
log27=1.431
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log(9*3)=1.431
log9+log3=1.431
log9=1.431-0.477
log9=0.954
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log(9*3)=1.431
log9+log3=1.431
log9=1.431-0.477
log9=0.954
Subham singh rathore said:
1 decade ago
log27=1.431
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log9=log3^2 then
2log3
2*0.477 = 0.954
log3^3=1.431
3log3=1.431
log3=1.431/3
log3=0.477
log9=log3^2 then
2log3
2*0.477 = 0.954
Olamikan adesanmi said:
1 decade ago
You divide 1. 431 by 3, making log3 subject of formula you get log 3 = 0.477
Arvind said:
1 decade ago
How come log3 value .477
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