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Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 4)
Height and Distance
4.
An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is:
21.6 m
23.2 m
24.72 m
None of these
Answer: Option
Explanation:

Let AB be the observer and CD be the tower.

Draw BE CD.

Then, CE = AB = 1.6 m,

      BE = AC = 203 m.

DE = tan 30° = 1
BE 3

DE = 203 m = 20 m.
3

CD = CE + DE = (1.6 + 20) m = 21.6 m.

Discussion:
18 comments Page 2 of 2.
Rocky said:   7 years ago
The correct answer is 61.6 so none of these is the correct option.
Ravina said:   8 years ago
I too had the Same doubt @Priya.

Please clear the doubt of as.
Priya58310 said:   9 years ago
Why they applied ''tan" what is the rule behind that?
Akshatha said:   7 years ago
@Rocky.

Yes, it is the right answer.
Lakshaya said:   8 years ago
Why be is Perpendicular to cd?
Dipakk said:   6 years ago
@Jatin.

Why EC & ED added?
Akshaya Prasad Sahoo said:   8 years ago
Why are you using tan 30?
Seeli said:   8 years ago
Why they not use cos 30?
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