Aptitude - Height and Distance - Discussion

Discussion Forum : Height and Distance - General Questions (Q.No. 4)
4.
An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30°. The height of the tower is:
21.6 m
23.2 m
24.72 m
None of these
Answer: Option
Explanation:

Let AB be the observer and CD be the tower.

Draw BE CD.

Then, CE = AB = 1.6 m,

      BE = AC = 203 m.

DE = tan 30° = 1
BE 3

DE = 203 m = 20 m.
3

CD = CE + DE = (1.6 + 20) m = 21.6 m.

Discussion:
18 comments Page 2 of 2.

Rocky said:   7 years ago
The correct answer is 61.6 so none of these is the correct option.

Midhun said:   7 years ago
@Akshaya Prasad.

We use tan, sin or cos depending upon what we want to get and what they have given in the question.

For example. If they give opposite side and you want to find the adjacent side. So, we will use a tan.

Akshatha said:   7 years ago
@Rocky.

Yes, it is the right answer.

Dipakk said:   6 years ago
@Jatin.

Why EC & ED added?

Kesavan said:   6 years ago
I'm not getting whether to use tan or cos. Please, anyone, clarify it in detail.
(1)

Pooja Kale said:   6 years ago
Remember basic rule,

If Finding :
Perpendicular : Sin
Hypotenuse : cos
Base : tan
(3)

Abirami said:   5 years ago
Opp/adj is cos not tan.

So, the answer is 31.6.

Thus none of these is the answer.
(3)

Vivek Sunny said:   4 years ago
No @Abirami..

cos = adjacent/hypotenuse

tan= opposite/adjacent

For simply, remember...

SOHCAHTOA

where,
s- Sin.
o- Opposite.
h- Hypotenuse.
c- Cos.
t- Tan.
(1)


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