Aptitude - Decimal Fraction - Discussion

Discussion Forum : Decimal Fraction - General Questions (Q.No. 8)
8.
The expression (11.98 x 11.98 + 11.98 x x + 0.02 x 0.02) will be a perfect square for x equal to:
0.02
0.2
0.04
0.4
Answer: Option
Explanation:

Given expression = (11.98)2 + (0.02)2 + 11.98 x x.

For the given expression to be a perfect square, we must have

11.98 x x = 2 x 11.98 x 0.02 or x   = 0.04

Discussion:
27 comments Page 1 of 3.

Nandaraj said:   1 decade ago
We know that.

(a + b) ^2 = a^2 + b^2 + 2ab.

Here a = 11.98.

b = 0.02.

2ab = 11.98x.

Therefore,

x = 2ab/11.98.

= (2*11.98*0.02) / 11.98 (11.98 cancel each other).

= 2*0.02.

x = 0.04.
(28)

Vanaja said:   1 year ago
=> (11.98)^2 + (0.02)^2 + 11.98 * x.
=>11.98*x = 2 * 11.98 * 0.02.
=>11.98*x = 0.04 * 11.98.
X = 0.04 * 11.98/11.98.
X = 0.04.
(8)

JSubba said:   7 years ago
Simple explanation.

For it to be a perfect square it should be like this: a^2 + 2ab + b^2 So what's missing in that equation to be a perfect square is 2b so here b is 0.02 so 2*0.02 = 0.04.
(6)

Sachin said:   3 years ago
@Nandaraj.

If we take b= 0. 2 then x = 0. 4, that will also be an answer.
(4)

Shweta said:   5 years ago
I think the ans should be 0.2.

(11.98)^2+2*11.98*0.02 +(0.02)^2.

2*0.02= 0.04=x^2.
x=0.2.
(3)

Abhilash said:   5 years ago
Compare with [ (a+b) ^2 ] formula.
(3)

Supriyo Ghosh said:   3 years ago
Well explained, Thanks @Nandaraj.
(1)

Ssundaram said:   8 years ago
Thanks for the detailed explanation @Tushar, @Ram, @Nandaraj.

Ivan said:   3 years ago
Thanks for explaining @Nandaraj.

Jaanu Jaanu said:   3 years ago
Thanks for the clear explanation @Nandaraj.


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