Aptitude - Decimal Fraction - Discussion

Discussion Forum : Decimal Fraction - General Questions (Q.No. 6)
6.
When 0.232323..... is converted into a fraction, then the result is:
1
5
2
9
23
99
23
100
Answer: Option
Explanation:
0.232323... = 0.23 = 23
99
Discussion:
26 comments Page 1 of 3.

Leela said:   1 decade ago
How? please explain.

Santhosh said:   1 decade ago
When a number repeating continiously, add number of 9's.

See formula number 6.

Formulas : http://www.indiabix.com/aptitude/decimal-fraction/formulas

Yuva said:   1 decade ago
I can't able to understand please explain.

SHIVDUTT THAPA said:   1 decade ago
LUK EVRY 1 ITS QUITE SIMPLE:

first let us suppose the decimal as x i.e x=0.232323... eq 1

after dat as we can see the digits r repeating after 2 digits

i.e. 23 so we just have to multiply the decimal no. by 100 and

dat will make 100x=23.232323...eq2

now simply subtract eq2 by 1 u will get the required result

Preeti said:   1 decade ago
Why it is only multiply by 100? Please explain.

Sachin said:   1 decade ago
If only 2 digits are repeating then you hav to multiply by 100.

If 3 digits are repeating the multiply by 1000 and so on.

Ruchi said:   1 decade ago
Write the repeated figures only once in the numerator and take as many nines in the denominator as is the number of repeating figures.

Chitra said:   1 decade ago
It is simple. All you need to do is just put as many as nines in denominator which are recurring or under the bar. In numerator remove the bar sign.

Sara khan said:   1 decade ago
Please explain this question 23 is repeated 3 times but we have added 9 (2 times in denominator not 3 times) why.

Poornamsh said:   1 decade ago
There are dots (....) after 23 i.e. 23 is repeated infinitely .232323232323232323...

But only two 'digits' - 2&3 are repeating so taken 2 9's.


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