Aptitude - Decimal Fraction - Discussion

Hay, I will explain it;
Let see;

x = 0.232323232323 ----------> 1
x = 23.23232323..../100 right

After cross multiplication we get,
100 x = 23.2323232323 -------> 2.

after subtracting Eqn 1 &2.
100x - x = 23.23232323 - 0.23232323...
99x = 23 right
Finally, we get;
x = 23/99 That's all.

6.4356565656.

Let's just solve the digits after.
0.4356565656.

According to the rule;
0.4356.

Now subtract 4356 from the first 2 digits which are not repeating;
4356-43=4313.
According to rule, you put 4313 in the nominator and in the denominator put 9900 (numbers which are not repeating are 2, so put two 9's and the remaining 2 are the repeating digits, so put 00 for that and the final digit will be 9900).

4313/9900.

6 + 4313/9900.

Or if you further solve it then 63713/9900 will be the final answer.

Thanks I hope it will help.

Thank you everyone for explaining.

Thank you everyone.

Let x=0.232323....
Then 100x=23.232323.
now,100x-x=23.
so,x=23/99.

Thanks.

How come 99? And why not 2/9?

Why not 2/9?

How come 99? Please explain.

How about 6.4356565656565656 then?

Here it is, (4356-56)/(9900).

How? please explain.