Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 8)
8.
The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is:
3
4
5
6
Answer: Option
Explanation:

P 1 + 20 n > 2P         6 n > 2.
100 5

Now, 6 x 6 x 6 x 6 > 2.
5 5 5 5

So, n = 4 years.

Discussion:
26 comments Page 2 of 3.

Shubham said:   9 years ago
What is the least number of complete years in which sum will become more than double itself at 12% per annum?

Given me the answer with clear explanation.
(1)

Ashok said:   9 years ago
@Kalyani.

In question, they asked how much of year will give the principal amount doubled so the only 2p is used.

Lokesh said:   8 years ago
Easy method.

How Will know n=72/r?

Dilip said:   9 years ago
@Kalyani

Suppose double principle then 2p.
Triple principle then 3p.

I hope you can understand.

Dhairya adhikari said:   9 years ago
Easy method:
n = 72/r,
n = 72/20 = 3.6 years,
n = 4 years approximately.

Abinash said:   2 decades ago
Dear friends, Can anybody tell me in brief how it is done please?

Kalyani said:   9 years ago
Why are we using 2p?

Ritesh said:   10 years ago
Hello @Anjali,

First take Amount = Rs. 5000 and Rate = 2%, Years = 1.

Then calculate SI, SI = PNR/100.

So, SI = 5000*1*2/100 = RS. 100.

[Here you are getting only interest].

Now calculate CI, CI = P(1+r)^n.

So, CI = 5000*(1+2/100)^1 = RS. 5100.

[Here we are getting Interest+Principal amount].

Anjali said:   10 years ago
I am unable to understand why are taking amount formula in place of CI. Please explain it.

Swathi said:   1 decade ago
Hi,

We are using > 2. Can you explain it?


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