Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 2)
2.
The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Re. 1. The sum (in Rs.) is:
Answer: Option
Explanation:
Let the sum be Rs. x. Then,
| C.I. = |  |
x |  |
1 + | 4 |  |
2 | - x |  |
= | |
676 | x | - x | |
= | 51 | x. |
| 100 | 625 | 625 |
| S.I. = | |
x x 4 x 2 | |
= | 2x | . |
| 100 | 25 |
 |
51x | - | 2x | = 1 |
| 625 | 25 |
x = 625.
Discussion:
149 comments Page 9 of 15.
KarthicK said:
9 years ago
@Sudharsan.
Clear explanation Thanks.
Clear explanation Thanks.
Shivesh said:
9 years ago
Derivation of this formula.
Principal x (r%/100)^2 = Difference between interests.
Principal x (r%/100)^2 = Difference between interests.
Nilesh said:
9 years ago
How 51/625 comes? Please explain that.
Prasad Mandati said:
8 years ago
Note:
If,
P= Principal sum x= R/100.
Now,
The difference between Compound and simple interests when compounded annually for two years is Px^2.
Similarly if the same is done for 3 years the difference would be P(x^3 + 3x^2).
Hope it helps you!
If,
P= Principal sum x= R/100.
Now,
The difference between Compound and simple interests when compounded annually for two years is Px^2.
Similarly if the same is done for 3 years the difference would be P(x^3 + 3x^2).
Hope it helps you!
Yashika said:
8 years ago
The SI = CI when the principal and rate are the same and time is ________.
Please give me the answer.
Please give me the answer.
Remya said:
8 years ago
Anu deposit some money in a bank. After 6 years he got 6500rs, then after 2 years, she got 7800 rs. The how much amount will she get after 10 years?
Can anyone solve this?
Can anyone solve this?
Chandan said:
8 years ago
Here, sum= (difference * 10000)/rate squre.
ADITYA VERMA said:
8 years ago
Short trick of this sum.
If the sum says diff. Of 2 years then apply::
P*R*R/100*100.
If the sum says diff. For 3 years then apply::
P*R*R (300+R)/100*100*100.
If the sum says diff. Of 2 years then apply::
P*R*R/100*100.
If the sum says diff. For 3 years then apply::
P*R*R (300+R)/100*100*100.
Hiten said:
8 years ago
Diff = pri*(r/100)sqr.
1 = x*(4/100)sqr,
1 = x*(1/25)sqr,
1 = x/625,
x=625.
1 = x*(4/100)sqr,
1 = x*(1/25)sqr,
1 = x/625,
x=625.
Hitesh said:
8 years ago
Why are we subtracting -x in the first part?
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