Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 14)
14.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
8
10
12
Cannot be determined
None of these
Answer: Option
Explanation:

15000 x 1 + R 2 - 15000 - 15000 x R x 2 = 96
100 100

15000 1 + R 2 - 1 - 2R = 96
100 100

15000 (100 + R)2 - 10000 - (200 x R) = 96
10000

R2 = 96 x 2 = 64
3

R = 8.

Rate = 8%.

Discussion:
32 comments Page 3 of 4.

Arshdeep said:   1 decade ago
Simply use formula difference=p*r*r/100*100.

Muniyasoda said:   1 decade ago
Explain more than two years?

Pratima said:   1 decade ago
Can any one provide shortcut for difference (CI-SI) questions for more than two years?

Manish said:   1 decade ago
Apply below simple formula and get the answer easily.

Difference = P(R)^2/(100)^2.

Lucky said:   1 decade ago
In 4th step how they done R^2=64 ?

If we solve it there should be R^2-200R=64 and this is a quadratic equation. Can anyone explain me how to solve this equation ?

Mudasir said:   1 decade ago
It's simply p(r/100)^2
p=1500,r=x,t=2yrs
Thus
15000(x/100)^2 it finally comes out like
x^2=64
x^2=8^2
x=8
Therefore rate=8%

Vimal said:   1 decade ago
Thanks prawin.

PRAWIN said:   1 decade ago
shortcut:
p = d (100/r)^2

15000 = 96*100*100/r^2

r^2 = 96*100*100/15000

r = 8.

NARENDRA said:   1 decade ago
SIMPLE FORMULA FOR TWO YEARS
C.I.-S.I.=P(R/100)*(R/100)
96=15000(R/100)(R/100)
R*R=960/15=64
R=8

Ravin said:   1 decade ago
Kindly explain in 3rd step howcum -1 would be showing...is this problem solve throuGh the LCM?


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