Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 14)
14.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
Answer: Option
Explanation:
![]() |
15000 x | ![]() |
1 + | R | ![]() |
2 | - 15000 | ![]() |
- | ![]() |
15000 x R x 2 | ![]() |
= 96 | |
100 | 100 |
![]() |
![]() |
![]() |
1 + | R | ![]() |
2 | - 1 - | 2R | ![]() |
= 96 |
100 | 100 |
![]() |
![]() |
(100 + R)2 - 10000 - (200 x R) | ![]() |
= 96 |
10000 |
![]() |
![]() |
96 x 2 | ![]() |
= 64 |
3 |
R = 8.
Rate = 8%.
Discussion:
32 comments Page 2 of 4.
Rahul said:
8 years ago
What will be solution, if time is 3years?
Somnath said:
8 years ago
@Prawin and @Velavan.
Thank you very much for giving the simple trick for the solution.
Thank you very much for giving the simple trick for the solution.
Ratan said:
8 years ago
Hi All ,
There is a shortcut method for this -
C.I. - S.I. = P*R^2/(100)^2.
so if we will put the values here it will be like this;
96 = 15000*R*R/10000,
64 = R*R,
So R =8.
There is a shortcut method for this -
C.I. - S.I. = P*R^2/(100)^2.
so if we will put the values here it will be like this;
96 = 15000*R*R/10000,
64 = R*R,
So R =8.
(3)
Shine said:
8 years ago
C.I - S.I (FOR 2 YEARS)= P (R/100)^2.
HENCE,
96 = 15000(R/100)^2.
Solve for R.
HENCE,
96 = 15000(R/100)^2.
Solve for R.
(1)
Ravi said:
9 years ago
For the difference between CI and SI for 2 years formula is p = d * (100/r)^2.
Bhaumik said:
9 years ago
@Muthu.
You explained beautifully, Thanks.
You explained beautifully, Thanks.
Anshul said:
9 years ago
Thanks, @A Velavan.
A Velavan said:
10 years ago
Difference between SI and CI when 2 years = p(r/100)^2.
96 = 15000(r/100)^2.
R*r = 32*2.
R^2 = 64.
R = 8.
96 = 15000(r/100)^2.
R*r = 32*2.
R^2 = 64.
R = 8.
Arshdeep said:
1 decade ago
Simply use formula difference=p*r*r/100*100.
Muniyasoda said:
1 decade ago
Explain more than two years?
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