Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 14)
14.
The difference between compound interest and simple interest on an amount of Rs. 15,000 for 2 years is Rs. 96. What is the rate of interest per annum?
8
10
12
Cannot be determined
None of these
Answer: Option
Explanation:

15000 x 1 + R 2 - 15000 - 15000 x R x 2 = 96
100 100

15000 1 + R 2 - 1 - 2R = 96
100 100

15000 (100 + R)2 - 10000 - (200 x R) = 96
10000

R2 = 96 x 2 = 64
3

R = 8.

Rate = 8%.

Discussion:
32 comments Page 2 of 4.

Rahul said:   8 years ago
What will be solution, if time is 3years?

Somnath said:   8 years ago
@Prawin and @Velavan.

Thank you very much for giving the simple trick for the solution.

Ratan said:   8 years ago
Hi All ,

There is a shortcut method for this -

C.I. - S.I. = P*R^2/(100)^2.
so if we will put the values here it will be like this;
96 = 15000*R*R/10000,
64 = R*R,
So R =8.
(3)

Shine said:   8 years ago
C.I - S.I (FOR 2 YEARS)= P (R/100)^2.

HENCE,
96 = 15000(R/100)^2.
Solve for R.
(1)

Ravi said:   9 years ago
For the difference between CI and SI for 2 years formula is p = d * (100/r)^2.

Bhaumik said:   9 years ago
@Muthu.

You explained beautifully, Thanks.

Anshul said:   9 years ago
Thanks, @A Velavan.

A Velavan said:   10 years ago
Difference between SI and CI when 2 years = p(r/100)^2.

96 = 15000(r/100)^2.

R*r = 32*2.

R^2 = 64.

R = 8.

Arshdeep said:   1 decade ago
Simply use formula difference=p*r*r/100*100.

Muniyasoda said:   1 decade ago
Explain more than two years?


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