Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 4)
4.
What is the difference between the compound interests on Rs. 5000 for 1
years at 4% per annum compounded yearly and half-yearly?

Answer: Option
Explanation:
C.I. when interest compounded yearly |
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= Rs. 5304. |
C.I. when interest is compounded half-yearly |
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= Rs. 5306.04 |
Difference = Rs. (5306.04 - 5304) = Rs. 2.04
Discussion:
85 comments Page 3 of 9.
Simran said:
1 decade ago
How to solve for year and a half when asked in a question please tell me now?
Shivanath said:
1 decade ago
What is the compound interest formula for full year. Tell the general nth year formula?
Deepthi said:
1 decade ago
How can we multiply 1/2 along with 4/100 when compounded annually?
Deepthi said:
1 decade ago
What is the actual equation for CI calculated annually?
Aswathi said:
1 decade ago
Explanation for the amount when compounded yearly is as below:
We learn from our formulas that when interest is compounded, annually but time is in fraction then it should be:
Amount = P*(1+r/100)^1*(1+(1/2*4)/100).
Please check general formula section 5.
We learn from our formulas that when interest is compounded, annually but time is in fraction then it should be:
Amount = P*(1+r/100)^1*(1+(1/2*4)/100).
Please check general formula section 5.
Gurpreet said:
1 decade ago
For yearly A = P[(1+R/100)*{1+(R/2)/100).
Then CI =A-P =304.
For half-yearly A = P(1+(R/2)/100)^3.
Then CI =A-P =306.04.
After that difference = CI(half yearly)-CI(yearly) = [(306.04)-304] = 2.04.
Then CI =A-P =304.
For half-yearly A = P(1+(R/2)/100)^3.
Then CI =A-P =306.04.
After that difference = CI(half yearly)-CI(yearly) = [(306.04)-304] = 2.04.
Stephen hawking said:
1 decade ago
Correct answer is 3.06.
CI 1 = 302.98 (not 304) and CI 2 = 306.04.
CI 1 = 302.98 (not 304) and CI 2 = 306.04.
Ranjeeta said:
1 decade ago
When the interest is compounded yearly, for that A = P(1+r/100)^t.
= 5000(1+4/100)^1.5 = 5302.98.
But here's what they have done I am not getting it for yearly compounding?
= 5000(1+4/100)^1.5 = 5302.98.
But here's what they have done I am not getting it for yearly compounding?
Sowmya` said:
1 decade ago
When time is in fraction formula changes as:
For ex time is: 1 1/2 years.
= p(1+r/100)^1*(1+(r/2)/100).
For ex time is: 1 1/2 years.
= p(1+r/100)^1*(1+(r/2)/100).
Prach said:
1 decade ago
How 51 come?
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