Aptitude - Compound Interest - Discussion

Discussion Forum : Compound Interest - General Questions (Q.No. 4)
4.
What is the difference between the compound interests on Rs. 5000 for 1 years at 4% per annum compounded yearly and half-yearly?
Rs. 2.04
Rs. 3.06
Rs. 4.80
Rs. 8.30
Answer: Option
Explanation:

C.I. when interest
compounded yearly    
= Rs. 5000 x 1 + 4 x 1 + x 4
100 100
= Rs. 5000 x 26 x 51
25 50
= Rs. 5304.

C.I. when interest is
compounded half-yearly
= Rs. 5000 x 1 + 2 3
100
= Rs. 5000 x 51 x 51 x 51
50 50 50
= Rs. 5306.04

Difference = Rs. (5306.04 - 5304) = Rs. 2.04

Discussion:
85 comments Page 2 of 9.

Afsha said:   1 decade ago
Finding it tuff to understand can anyone please make it easy for me from first step.

Tarun said:   1 decade ago
When interest is compounded annually,

Amount = p[1+(r/100)]^t.

When interest is compounded half yearly,

Amount = p[1+(r/2x100)]^2t.

Qutub said:   1 decade ago
How "C. I. When interest compounded yearly" is calculated?

Shakti said:   1 decade ago
When interest is compounded annually~ Yearly,

Amount(A) = p[1+(r/100)]^t.

CI = P-A.x

Arslan said:   1 decade ago
As C.I = [1+4/100]^3/2.
= [1+.03]^3/2.
= 5302.980298.

Why?

Akshay said:   1 decade ago
Why is is 1+[(1/2)*4/100] when it should be 1+(4/100)^1/2 when the interest is compounded annually.

Roop said:   1 decade ago
Why 1/2*4 instead of (1+4/100)^1/2 ?

Roop said:   1 decade ago
@Akshay and @Arslan.

When time is in fraction that is 3/2 then the formula is:
A = P[(1+R/100)*{1+(R/2)/100).

Sneh said:   1 decade ago
How we can compound half yearly means I did not understand how 3 can come means n=3 ?

Divya said:   1 decade ago
Compound interest indicates interest on interest.

So we can calculate it as:
CI1 = 5000*(4/100)*1 = 200.
But I don't know to calculate, CI2 for 1/2 year.

Such that compound interest CI = CI1+CI2.


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