Aptitude - Compound Interest - Discussion
Discussion Forum : Compound Interest - General Questions (Q.No. 1)
1.
A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:
Answer: Option
Explanation:
Amount |
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= Rs. 3321. |
C.I. = Rs. (3321 - 3200) = Rs. 121
Discussion:
220 comments Page 1 of 22.
Akhila said:
2 decades ago
How did you get 41/40 am not able to get that value please help me.
Sundar said:
2 decades ago
Hi Akhila,
= 1 + (5/(2 x 100)
= 1 + (5/200)
= 1 + (1/40)
= (40 + 1)/40
= 41/40
Next step (41/40)^2
= 41/40 x 41/40
...
Hope you understand. Have a nice day!
= 1 + (5/(2 x 100)
= 1 + (5/200)
= 1 + (1/40)
= (40 + 1)/40
= 41/40
Next step (41/40)^2
= 41/40 x 41/40
...
Hope you understand. Have a nice day!
SIPU said:
1 decade ago
YA SUNDER IS CORRECT...
Bala said:
1 decade ago
Its a basic thing. Where did you get 3200 in this problem?
Manju said:
1 decade ago
Hai, where did you get from this value 3200.
Dinesh guptha said:
1 decade ago
I think customer deposits per year 3200.
So they subtracted 3200 with that final amount it seems.
So they subtracted 3200 with that final amount it seems.
Dinesh said:
1 decade ago
Can anyone clear me the first step.
Venkat said:
1 decade ago
venkst:simple customer deposited twice
1600*2=3200
1600*2=3200
Boney said:
1 decade ago
I dont understand the 2nd term in the expression
Amount=1600[1+(1/2)*(5/100)]^2+ 1600[1+(5/2*100)]
Amount compounded half yearly is A=P[1+r/2*100)]^2
Don't understand what this term doing 1600[1+(5/2*100)]
Someone tell me
Amount=1600[1+(1/2)*(5/100)]^2+ 1600[1+(5/2*100)]
Amount compounded half yearly is A=P[1+r/2*100)]^2
Don't understand what this term doing 1600[1+(5/2*100)]
Someone tell me
(1)
Lavanya said:
1 decade ago
I too dint understand d first step
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