Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 4)
4.
A watch which gains 5 seconds in 3 minutes was set right at 7 a.m. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:
59 7 min. past 3
12
4 p.m.
58 7 min. past 3
11
2 3 min. past 4
11
Answer: Option
Explanation:

Time from 7 a.m. to 4.15 p.m. = 9 hrs 15 min. = 37 hrs.
4

3 min. 5 sec. of this clock = 3 min. of the correct clock.

37 hrs of this clock = 1 hrs of the correct clock.
720 20

37 hrs of this clock = 1 x 720 x 37 hrs of the correct clock.
4 20 37 4

      = 9 hrs of the correct clock.

The correct time is 9 hrs after 7 a.m. i.e., 4 p.m.

Discussion:
154 comments Page 10 of 16.

Sachin said:   10 years ago
A clock is showing 14:19, what will time after 14399999991 min.

Pooja said:   1 decade ago
From 7 am to 4 pm, We are getting 900 sec gain, which is 900/60 = 15 min gain.

Now, the question has asked what will be the actual time when it is showing 4:15 pm.

Now, at 4 pm it already has gained 15 min, i.e. it is showing 4:15 pm already.

I was doing it wrong when I took 900 + 25 sec, where 25 sec was for 4 to 4:15 pm, which is wrong.

We are not asked to calculate time at 4:15 pm, we are asked for 4 pm.
(1)

Kasinath@Hyd said:   1 decade ago
7am to 4:15====>is 9hrs and 15 min.

3min ====EXCEEDS===> 5sec.

15min==============> 25sec equation (1).

1hr (60min) =========> 100sec.

====================

======So on=========

====================

9hr=================> 900sec equation (2).

9:15 == equation(1)+equation(2) => 925 sec i.e. in 9:15 min time exceeded by 15 min.

Therefore time is 4 pm and not 4:15.

Vivek said:   1 decade ago
Correct answer is (A).

In 3 min fast is - 5 sec.
In 1 min fast is - 5/3 sec.

In 60 min fast is - 5/3*60 - 100 sec.
So 1 hr fast is - 100 sec.
In 9 hr 25 sec - 925 sec.

Si actually fast is - 900 sec + 25 sec = 900/60+25/60 = 15 5/12 min.

So actual time is = 3 hr 59*7/12.

Sasi said:   1 decade ago
For 3 mins 5 sec gain.

i.e for 180 sec clock shows 185 sec.

That means for every hour it's shows 1 min 40 sec more than actual time.

We need to calculate actual time when clock shows 4:15 pm.

Given that time set at 7 am so the difference between 7 to 4:15 is 9:15 hours.

Clock showing us 1 min 40 secs more for every hour then for 9 hours 15 secs it shows 15 mins fast.

So the answer is 4 pm.

Sai kumar said:   1 decade ago
3 past 5 seconds = 3 mins. There is no such one in the question.

How you took that one? Can you explain clearly?

Javad said:   1 decade ago
Leave all worries guys think practically.

For 3 min 5 sec gain.

Then for 15 min 25 sec, for 1 hour 100 sec i.e. 1.5 min and 10 sec.

For 9 hr 15 min it is 13.5 (i.e. 1.5*9) + 1.5 (i.e. Remaining 10 sec*9).

So totally 13.5+1.5= 15 min gain.

That is 4op o'clock.

Ankita said:   1 decade ago
How 37/4 becomes not understood?

Anaj Hussain said:   1 decade ago
How we got 37/720 ? please tell me any one.

Bharath said:   1 decade ago
Time between 7AM to 4.15PM = 9 hours 15 Minutes = 9+15/60 hours = 9+1/4 hours = ((9*4)+1)/4 hours = (36+1)/4 hours = 37/4 hours.

Now 3 Minutes 5 seconds of this clock = 3 minutes of the correct clock--------(1).

So, by converting above into hours we get,
First we convert into minutes,

3+5/60 = 3+1/12 = ((3*12)+1)/12 = 37/12 ---------(2).

Now we convert above result into Hours, we get 37/12*60 = 37/720 hours.

And on right side of equation 1, 3 minutes after converting into hours becomes 3/60 hours that is 1/20 hours----------(3).

So from equations 1, 2, 3 we get,
37/720 hours of this clock = 1/20 hours of correct clock.

Then 37/4 hours of this clock = (1/20)*(37/4)*(720/37) = 9 hours.
Therefore correct time is 7+9 hours = 16 Hours on 24 clock, that is 4PM on 12 hours clock.
(1)


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