Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 4)
4.
A watch which gains 5 seconds in 3 minutes was set right at 7 a.m. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:
59 7 min. past 3
12
4 p.m.
58 7 min. past 3
11
2 3 min. past 4
11
Answer: Option
Explanation:

Time from 7 a.m. to 4.15 p.m. = 9 hrs 15 min. = 37 hrs.
4

3 min. 5 sec. of this clock = 3 min. of the correct clock.

37 hrs of this clock = 1 hrs of the correct clock.
720 20

37 hrs of this clock = 1 x 720 x 37 hrs of the correct clock.
4 20 37 4

      = 9 hrs of the correct clock.

The correct time is 9 hrs after 7 a.m. i.e., 4 p.m.

Discussion:
154 comments Page 1 of 16.

Bharath said:   1 decade ago
Time between 7AM to 4.15PM = 9 hours 15 Minutes = 9+15/60 hours = 9+1/4 hours = ((9*4)+1)/4 hours = (36+1)/4 hours = 37/4 hours.

Now 3 Minutes 5 seconds of this clock = 3 minutes of the correct clock--------(1).

So, by converting above into hours we get,
First we convert into minutes,

3+5/60 = 3+1/12 = ((3*12)+1)/12 = 37/12 ---------(2).

Now we convert above result into Hours, we get 37/12*60 = 37/720 hours.

And on right side of equation 1, 3 minutes after converting into hours becomes 3/60 hours that is 1/20 hours----------(3).

So from equations 1, 2, 3 we get,
37/720 hours of this clock = 1/20 hours of correct clock.

Then 37/4 hours of this clock = (1/20)*(37/4)*(720/37) = 9 hours.
Therefore correct time is 7+9 hours = 16 Hours on 24 clock, that is 4PM on 12 hours clock.
(1)

Akash Gupta said:   8 years ago
Another view can be:

In 3 minutes the error is 5 seconds, so every hour it gains 100 seconds.

Correct Clock ----------------------------> Wrong Clock
7 hrs ----------------------------> 7 hrs
8 hrs ----------------------------> 8hrs 100 sec
9 hrs ----------------------------> 9 hrs 200 sec
10 hrs ----------------------------> 10 hrs 300 sec
11 hrs ----------------------------> 11 hrs 400 sec
12 hrs ----------------------------> 12 hrs 500 sec
1 hrs ----------------------------> 1 hrs 600 sec
2 hrs ----------------------------> 2 hrs 700 sec
3 hrs ----------------------------> 3 hrs 800 sec
4 hrs ----------------------------> 4 hrs 900 sec ----> 4 hrs 15 minutes

Sundar said:   1 decade ago
To: Nitin

You are wrong. The given answer is correct. Don't get confused.

Let me explain in simple manner:

Error Clock :: Original Clock

3 min 5 sec :: 3 min

185 sec :: 180 sec

[9 hr 15 min = 555 min = 33300 sec]

33300 sec :: (180/185 x 33300) sec

33300 sec :: 32400 sec

333000sec = 9 hrs 15 min :: 32400 sec = 9 hrs [:. 32400/3600 = 9]

So,
Time passed by Error clock = 9 hrs 15 min.
Time passed by Original clock = 9 hrs.

Therefore, 9 hrs after 7 am is 4 pm.


Note: What was wrong in Nitin's explanation?

555/3 <--- Problem is here.

It should be

555 min/3 min 5 sec [or] 33300/185

Please think twice before solve problem. Hope this will help you. All the best!
(1)

Kavya said:   8 years ago
Option A is the right answer.

Explanation: for every 3 minutes its gaining 5 seconds.
3 min = 5 sec ------------------(1)
So in 1 hour it will gain.
(60 min * 5 sec) / 3 min = 100 sec-------------(2)
So in 9 hours( 7 a.m. to 4 p.m) it will gain.
(100 sec * 9 hrs) = 900 sec---------------------(3)
In 15 min it will gain (15 min * 5 sec) / 3 min= 25 sec------------(4)
Total in 9 hours 15 min( 7 am to 4:15pm) it will gain = 925sec.
Now convert 925 seconds into minutes.
i.e, 925/60 = 15.416667 (this is not a approximation problem. We cannot neglect the numbers
After decimal point) = 185/12 = 15 5/12.
So now, 4:15 -(minus)15 5/12 = 3:59:35 = 59 7/12 past 3 pm.

Vinay Chik Baraik said:   8 years ago
It's given that error clock gains 5 seconds in each 3 minutes of perfect clock.
So, 3min 5sec of error clock = 3min of perfect clock.

Or, [3+(5/60)] min of error clock = 3min of perfect clock. (185s of error clock = 180s perfect clock)
Or, (37/12) min of error clock = 3min of perfect clock
Or 1 min of error clock = 3*12/37 min of perfect clock =36/37.

Now error clock moved from 7am to 4:15pm = 9hr 15min = ( 9*60 + 15 )min = 555min.
So in 555 min of error clock = (36/37)*555 min of perfect clock = 540min of perfect clock.
= (540/60) hr = 9 hr of perfect clock.
So 9hr from 7am is 4pm. Thus the answer is [B] 4 p.m.

Vithya said:   9 years ago
@Manisha.

I hope this will help you.

5 sec gained in 3 min, so,convert 3 min into 1 hr (for convenience).

(5*20)sec gained in (3*20)min.
100 sec gained in 1 hr (60 min=1 hr).
The total duration b/w 7 am to 4.15 pm = 9.15 (9 hr 15 min).

(15 min = 1/4 hr) so, 9.15 = 9 hr + 1/4 hr = 37/4 hrs.

In 1 hr 100 sec gained so, in 37/4 hrs ?
(37/4)*100 = 37*25 = 925 sec.

Convert sec into min:
925 sec = 925/60 min = 15.41 min (approx 15 min).

True time calculation:

Time is to be gained so, clock running fast. To find the true time , we need to subtract 15 min from 4.15.

Then, true time = 4.15 - 15 min = 4 pm.

Abhishek Gupta said:   1 year ago
It gains 5 seconds in 3 minutes.

3min = 5seconds
3min = 1/12 min
1min = 1/36 min

Let correct watch shows time which is x min ahead of 7 am.

Then minutes gained by faulty clock = x/36minutes.

So, the faulty clock is ahead of 7 am by (x + x/36)min or 37x/36 min.

but in question, it is given faulty clock shows 4.15 pm which is (9*60+15)min or 555min ahead of 7 am.

So,
37x/36 = 555

x = 540min or 9 hrs

So, the correct time is 7 am + 9hr = 4 pm.

Note: We have to calculate the time gained by the faulty clock in terms of the correct clock not in terms of the faulty clock time given in the question
(5)

Ad_Mgt said:   1 decade ago
The problem is with the calculation of 9hr 15min=555 minutes. This value is associated with the erroneous clock. You need to convert it for the true clock. As per data, we can write,

3 mins in the true clock equals 3 min 5 seconds (3+5/60 or 37/12 minutes) in erroneous clock. Thus we have

37/12 mins of erroneous clock equals 3 mins of true clock.
1 mins of erroneous clock equals (3*12/37) mins of true clock.
555 mins of erroneous clock equals (3*12*555/37)=540 mins of true clock.

540 minutes = 540/60 hours = 9 hours. The actual time is (7+9) hours = 16 hours = 4P.M.

Jayasree said:   8 years ago
Consider the ratio of the speed of original clock : error clock;.

By the time original clock covers 180 secs, error clock covers 185 secs.
therefore speed ratio is 180(original) : 185 (error).
==> 36:37.
Error clock covers 9 hours 15 mins= 9 1/4 hours = 37/4 hours.
Now solving by ratio proportion,

Speed --- time covered(in hours)
37 --- 37/4 ---------> Error clock
36 --- ? ---------> Original clock

Time covered by original clock is ==> 37/4 * 36/37.
==>9 hours i.e, clock shows at 4.00 pm.

Anurag said:   1 decade ago
In 3 MIN = The clock gains 5 sec.
in 60 min(3 * 20) = clock gains 100 sec(5 * 20)
= i.e 100/60 min
= 5/3 min
So , If correct clock shows 1 hour=den da wrong clock shows 1 hr 5/3 min..
i.e
1 hr=1 hr 5/3 min
=1 * 5/(3*60) hour (convert to hour)
=37/36 hour

But we need to do reverse..
i.e
37/36 hrs(in wrong clock) = 1 hr
1 hour in wrong clock = 1/(37/36)=36/37 hr

9hr 15min=37/4 hrs

So
37/4 hours in wrong clock =36/37 * 37/4
= 9
So 7 a.m + 9 hrs= 4 pm ....

I hope every1 got it...


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