Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 6)
6.
At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?
Answer: Option
Explanation:
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.
At 7 o'clock, they are 25 min. spaces apart.
Minute hand will have to gain only 5 min. spaces.
55 min. spaces are gained in 60 min.
| 5 min. spaces are gained in |  |
60 | x 5 |  min |
= 5 | 5 | min. |
| 55 | 11 |
| Required time = 5 |
5 | min. past 7. |
| 11 |
Discussion:
70 comments Page 3 of 7.
Karthik said:
1 decade ago
In 1 hour the min hand will gain 60 min and the hour hand will gain 5 min (i.e if the time is 5 the hour hand will take 5 min spaces to reach 6) so 60-5= 55
Did you understand this?
Did you understand this?
Santhoshi vempati said:
5 years ago
The angle between minute's hand hour's hand=30H-(11/2)M.
H = hours; M = minutes.
Given hour's and minute's is a straight line, so the angle is 180degrees.
180 = 30(7) - (11/2) * M,
M = 60/7 = 5 5/11,
So, the answer is 5 5/11min.past 7.
H = hours; M = minutes.
Given hour's and minute's is a straight line, so the angle is 180degrees.
180 = 30(7) - (11/2) * M,
M = 60/7 = 5 5/11,
So, the answer is 5 5/11min.past 7.
(9)
Sandun said:
9 years ago
Another way to do this.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.
If we put this in to an equation and we get x = 5 5\11.
Rintu said:
9 years ago
To from 180d between 7:0 to 8:0, the minute hand has to gain (35 - 30) = 5 min space.
As in 1 min =12/11 min gain.
Therfore in 5 min=12/11 * 5 = 5 * 5/11 min.
As in 1 min =12/11 min gain.
Therfore in 5 min=12/11 * 5 = 5 * 5/11 min.
Vash said:
1 decade ago
Let x = to minutes and x/12 = to hour.
x = 35+x/12-30 = 12x = 420+x-360.
11x = 60. 35 minutes = 7 o'clock.
I put -30 because x = 60/11 directly opposite to each other = 5.45 or 5 5/11.
180 degrees.
x = 35+x/12-30 = 12x = 420+x-360.
11x = 60. 35 minutes = 7 o'clock.
I put -30 because x = 60/11 directly opposite to each other = 5.45 or 5 5/11.
180 degrees.
Hir@nm@y said:
8 years ago
At first you multiple 1st hours by 5 (7*5=35),
Then you substitute 30 from the multiple values, (35-30=5),
That's the answer.
5* 5/11 [by rules of (x* x/11)].
That's answer will 7: 5* 5/11
Then you substitute 30 from the multiple values, (35-30=5),
That's the answer.
5* 5/11 [by rules of (x* x/11)].
That's answer will 7: 5* 5/11
Sushil said:
1 decade ago
Given mh&hh are straight, so angle is 180.
As per formula:
(hh*30) + (x/2) - (x*6) = 180.
Here x is min and hh is 7 by solving x we will get x as 5+5/11. So D is the answer.
As per formula:
(hh*30) + (x/2) - (x*6) = 180.
Here x is min and hh is 7 by solving x we will get x as 5+5/11. So D is the answer.
Prasanna said:
1 decade ago
I have a problem with this answer.
Both hh and mh will meet at 7 i.e. time is 7:35 but exact answer is 7:35+35/11 = 7:35+32/11 = 7:38 2/11.
Then how it will 5 5/11 past to 7?
Both hh and mh will meet at 7 i.e. time is 7:35 but exact answer is 7:35+35/11 = 7:35+32/11 = 7:38 2/11.
Then how it will 5 5/11 past to 7?
Riya shah said:
9 years ago
Shortcut formula:
ANGLE = 30*H - 11/2M.
Together Means angle consider as zero.
Put into the formula.
0 = 30 * 7 - 11/2M.
11/2M = 210.
Imp together consider as zero.
ANGLE = 30*H - 11/2M.
Together Means angle consider as zero.
Put into the formula.
0 = 30 * 7 - 11/2M.
11/2M = 210.
Imp together consider as zero.
Hari said:
1 decade ago
See from clock 3.
At 1 o'clock they are 55 min spaces apart.
2 o'clock......50 min......
3....... 45 min.......
4....... 40 min.......
.
.
.
7........ 25 min......
At 1 o'clock they are 55 min spaces apart.
2 o'clock......50 min......
3....... 45 min.......
4....... 40 min.......
.
.
.
7........ 25 min......
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