# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 6)

6.

At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?

Answer: Option

Explanation:

When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.

At 7 o'clock, they are 25 min. spaces apart.

Minute hand will have to gain only 5 min. spaces.

55 min. spaces are gained in 60 min.

5 min. spaces are gained in | 60 | x 5 | min | = 5 | 5 | min. | |

55 | 11 |

Required time = 5 | 5 | min. past 7. |

11 |

Discussion:

68 comments Page 3 of 7.
Shubham satpathy said:
7 years ago

Trick is 60/11 *( time +or - 6).

So between 7 to 8. Time is smaller one is.7 now here 7 is big than 6 so formula become 60/11 * (7-6) which is the answer.

So between 7 to 8. Time is smaller one is.7 now here 7 is big than 6 so formula become 60/11 * (7-6) which is the answer.

Jaanu said:
7 years ago

Use this formula to find angle :

Angle=((11/2)*minutes )-30* hour.

Between 7 and 8 means that the time would be something around 7. So consider 7 hours and x minutes.

180 = (11* x )/2 - 30 * 7.

210 - 180 = 11*x /2.

30 = 11*x /2.

30*2 = 11x,

60 = 11x,

X = 5.5/11.

That is 7 hours and 5 5/11 min.

Angle=((11/2)*minutes )-30* hour.

Between 7 and 8 means that the time would be something around 7. So consider 7 hours and x minutes.

180 = (11* x )/2 - 30 * 7.

210 - 180 = 11*x /2.

30 = 11*x /2.

30*2 = 11x,

60 = 11x,

X = 5.5/11.

That is 7 hours and 5 5/11 min.

G Nagesh said:
7 years ago

How is come 5*5/11?

Please explain anyone.

Please explain anyone.

Shanur Rahman said:
7 years ago

@Sharmistha.

Minute hand gains 55 minutes on the hour hand.

Minute hand gains 55 minutes on the hour hand.

Hrushi said:
7 years ago

How 5*5/11 come?

Please explain.

Please explain.

NAVI said:
7 years ago

I didn't understand the question. Can anyone help me?

Rintu said:
8 years ago

To from 180d between 7:0 to 8:0, the minute hand has to gain (35 - 30) = 5 min space.

As in 1 min =12/11 min gain.

Therfore in 5 min=12/11 * 5 = 5 * 5/11 min.

As in 1 min =12/11 min gain.

Therfore in 5 min=12/11 * 5 = 5 * 5/11 min.

Shiv said:
8 years ago

Thanks for your solution @Shekhar.

Prasanna said:
8 years ago

Here, is some Equation:

Angle between hands = [(Hour Hand * 30) + (Minute hand * 1/2)] - Minute hand * 6.

(Hour Hand * 30) -> Because At 1 o'clock it will be 30 deg so at 7 it will be 150 deg.

Minute hand * 1/2 -> Hour hand moves 1/2 deg per min.

Minute hand * 6 -> Minute hand moves 6 deg per min.

180 = [7 * 30 + x/2] - 6x.

So, the answer is 5 5/1.

Angle between hands = [(Hour Hand * 30) + (Minute hand * 1/2)] - Minute hand * 6.

(Hour Hand * 30) -> Because At 1 o'clock it will be 30 deg so at 7 it will be 150 deg.

Minute hand * 1/2 -> Hour hand moves 1/2 deg per min.

Minute hand * 6 -> Minute hand moves 6 deg per min.

180 = [7 * 30 + x/2] - 6x.

So, the answer is 5 5/1.

Sandun said:
8 years ago

Another way to do this.

The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.

If we put this in to an equation and we get x = 5 5\11.

The angle created when the time is 7 o' clock is 150*. So we have to add the extra gained by minute hand and to subtract the angle lost by hour hand.

If we put this in to an equation and we get x = 5 5\11.

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