# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 6)

6.

At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but, not together?

Answer: Option

Explanation:

When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.

At 7 o'clock, they are 25 min. spaces apart.

Minute hand will have to gain only 5 min. spaces.

55 min. spaces are gained in 60 min.

5 min. spaces are gained in | 60 | x 5 | min | = 5 | 5 | min. | |

55 | 11 |

Required time = 5 | 5 | min. past 7. |

11 |

Discussion:

68 comments Page 2 of 7.
Tejasri Samala said:
5 years ago

The simple formula to find is;

1. [(5h-30)*12/11] for h>6.

2. [(5h+30)*12/11]for h<6.

1. [(5h-30)*12/11] for h>6.

2. [(5h+30)*12/11]for h<6.

(3)

Rohit said:
5 years ago

The formula is 11/2min-30 hour.

Why are we reversing this formula in this question? Please tell me.

Why are we reversing this formula in this question? Please tell me.

(1)

Bombiyah said:
5 years ago

The angle formed from 12 o'clock to 7 o'clock is 210°.

Use this formula:

2/11 (angle formed (+) or (-) 180°)

Add 180 when the clock hands coincide, subtract when they are not.

Since, not coincide subtract it,

=2/11(210 * 180°)

= 60/11 or 5 5/11.

Use this formula:

2/11 (angle formed (+) or (-) 180°)

Add 180 when the clock hands coincide, subtract when they are not.

Since, not coincide subtract it,

=2/11(210 * 180°)

= 60/11 or 5 5/11.

Joshua Thangliana said:
5 years ago

Degree= 30H - 5.5M.

straight line= 180 °

=> 180= 30*7 - 5.5M.

=> M= 60/11.

So, Answer= 7 hours 60/11 min.

straight line= 180 °

=> 180= 30*7 - 5.5M.

=> M= 60/11.

So, Answer= 7 hours 60/11 min.

(1)

Tehsin said:
6 years ago

I couldn't get it how 55 min required to gain 60 min spaces. I mean they are min spaces so why not 60 min spaces be in 60 min? please someone explain!

(1)

Bhushan suriya said:
6 years ago

(210-6a)+(30/60)a = 180.

I think this will be the perfect solution.

I think this will be the perfect solution.

John said:
6 years ago

@Vivek Jain.

In 1 hr minute, min hand covers 60 min and hr hand covers 5 min. Comparing both minute hand gains 55 min in 1 hr.

In 1 hr minute, min hand covers 60 min and hr hand covers 5 min. Comparing both minute hand gains 55 min in 1 hr.

Hir@nm@y said:
6 years ago

At first you multiple 1st hours by 5 (7*5=35),

Then you substitute 30 from the multiple values, (35-30=5),

That's the answer.

5* 5/11 [by rules of (x* x/11)].

That's answer will 7: 5* 5/11

Then you substitute 30 from the multiple values, (35-30=5),

That's the answer.

5* 5/11 [by rules of (x* x/11)].

That's answer will 7: 5* 5/11

Arika said:
6 years ago

Please solve how to find between 8 &9 o'clock as the same process?

Sushma R said:
6 years ago

A=30H-5.5M.

Where A=180',

H=7,

Now,

180=30*7-5.5M,

30=5.5M,

M=300/55,

M=5*5/11.

Where A=180',

H=7,

Now,

180=30*7-5.5M,

30=5.5M,

M=300/55,

M=5*5/11.

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