Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 15)
15.
At what time between 9 and 10 o'clock will the hands of a watch be together?
45 min. past 9
50 min. past 9
49 1 min. past 9
11
48 2 min. past 9
11
Answer: Option
Explanation:

To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.

55 min. spaces gained in 60 min.

45 min. spaces are gained in 60 x 45 min or 49 1 min.
55 11

The hands are together at 49 1 min. past 9.
11

Discussion:
48 comments Page 4 of 5.

Shree Hema said:   2 decades ago
@manish
better use this formula
theta=11(m)/2-30(h)
if both hands coincide degree ll be 0
if both hands r in opposite direction degree will be 180
if both hands r in right angle degree will be 90
here it coincides so 0 degree
we have to find min only so keep that parameter(m) as it is, use minimum hour for hour parameter(h=9)
0=11(m)/2-30(9)
m=49 1/11
Got It???

Krishnadas said:   2 decades ago
@sree. Good work. But is this formula standard?

Avijeetkumar said:   2 decades ago
@shree. You are right.

Senthamizh said:   2 decades ago
@Shree: is that standard formula???

Anil said:   1 decade ago
If time is between x and y:

[x*5+angle]*(12/11) past x.

Pradeep said:   1 decade ago
Here we can use the formula:
theta=11(m)/2-30(h)
same direction means 0 degree; hour=9
180=11(m)/2-30(9)
m=49 1/11

Jasraj khatri said:   1 decade ago
When minute hand reach to 9, hour hand reach near to 10. Then why you count 45 spaces?

Aarthi said:   1 decade ago
Can you tell me the correct explanation?

$hr!dhar said:   1 decade ago
@Shree Hema: Hats Off To u!!! Awsm Formula!!
thnks ;)

can u plz give derivation of formula...

Goku said:   1 decade ago
Keep it simple friends! Just use this formula.

12/11 (minutes to be gained). See in the question between 9 to 10'o clock we know that at 9:45 the hands will coincide so 45 minutes is to be gained from 9 o'clock.

So 12/11* (45) =49 1/9 (Answer).


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