# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 15)

15.

At what time between 9 and 10 o'clock will the hands of a watch be together?

Answer: Option

Explanation:

To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.

55 min. spaces gained in 60 min.

45 min. spaces are gained in | 60 | x 45 | min or 49 | 1 | min. | |

55 | 11 |

The hands are together at 49 | 1 | min. past 9. |

11 |

Discussion:

47 comments Page 2 of 5.
A k singh said:
9 years ago

What master formula you are giving its not applicable to a single question we are doing. All the time its having negative sign error. I don't think so that is the master formula but can say this is confusing the whole concept we read till now.

Vipin said:
1 decade ago

Alternative method::

Let the minutes covered when d situation occurs = x

now,

(total degrees covered by minute hand) - (total degrees covered by hr hand)= (outer angle between 12 and 9) i.e.

6x - x/2 = 270

x=540/11 which is our ans. :)

Let the minutes covered when d situation occurs = x

now,

(total degrees covered by minute hand) - (total degrees covered by hr hand)= (outer angle between 12 and 9) i.e.

6x - x/2 = 270

x=540/11 which is our ans. :)

Nisha lakshmi said:
5 years ago

BTW 9 and 10 the hand of the clock will be together at 9:45(min and hr hand coincides).

Since 55 min gained by min hand in 60 min.

Thus 1 min gained by min hand in 60/55 min.

Now 45 min gained by min hand in 60/55 * 45 = 540/11 min.

Since 55 min gained by min hand in 60 min.

Thus 1 min gained by min hand in 60/55 min.

Now 45 min gained by min hand in 60/55 * 45 = 540/11 min.

V.k said:
1 decade ago

Total distance the minute hand cover with respect to hour hand is 270'

And the relative speed is 5.5.

So the time to cover is,

270/5.5 = 540/11.

And the relative speed is 5.5.

So the time to cover is,

270/5.5 = 540/11.

Chandresh said:
10 years ago

You can try this way also.

360 = 30(10)-(11/2)m.

360-300 = (11/2)m.

(60*2)/11 = m.

m = 120/11;

Now just do: 60-(120/11) = 540/11 = 49.1/11.

360 = 30(10)-(11/2)m.

360-300 = (11/2)m.

(60*2)/11 = m.

m = 120/11;

Now just do: 60-(120/11) = 540/11 = 49.1/11.

Krish said:
1 decade ago

Sakshi,

The question is between 9 and 10 both the hands must coincide,.

So for the minute hand to reach 9 it has to gain 45 minute spaces.

The question is between 9 and 10 both the hands must coincide,.

So for the minute hand to reach 9 it has to gain 45 minute spaces.

Sivanandhini chandrasekar said:
10 months ago

Formula :

Θ = |11M/2 - 30H|.

0⁰=|11M/2 - 30*9|.

= 11M/2 - 270.

0⁰+270⁰=11M/2.

270*2/11=M.

540/11=M.

M = 49 1/11.

Θ = |11M/2 - 30H|.

0⁰=|11M/2 - 30*9|.

= 11M/2 - 270.

0⁰+270⁰=11M/2.

270*2/11=M.

540/11=M.

M = 49 1/11.

(5)

Irfan Qureshi said:
6 years ago

Formula : (11/2)M - 30*H = 0.

We have to find min so put H and get M.

M=min.

H=Hour.

put the value and get the answer in Min.

We have to find min so put H and get M.

M=min.

H=Hour.

put the value and get the answer in Min.

Jeet said:
9 years ago

In Q6 at 7, they are 25 mins apart, but in this Q at 9 they are 45 mins apart, is the angle measured clockwise/ anti clockwise?

Pradeep said:
1 decade ago

Here we can use the formula:

theta=11(m)/2-30(h)

same direction means 0 degree; hour=9

180=11(m)/2-30(9)

m=49 1/11

theta=11(m)/2-30(h)

same direction means 0 degree; hour=9

180=11(m)/2-30(9)

m=49 1/11

Post your comments here:

Quick links

Quantitative Aptitude

Verbal (English)

Reasoning

Programming

Interview

Placement Papers