Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 15)
15.
At what time between 9 and 10 o'clock will the hands of a watch be together?
45 min. past 9
50 min. past 9
49 1 min. past 9
11
48 2 min. past 9
11
Answer: Option
Explanation:

To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.

55 min. spaces gained in 60 min.

45 min. spaces are gained in 60 x 45 min or 49 1 min.
55 11

The hands are together at 49 1 min. past 9.
11

Discussion:
47 comments Page 2 of 5.

A k singh said:   9 years ago
What master formula you are giving its not applicable to a single question we are doing. All the time its having negative sign error. I don't think so that is the master formula but can say this is confusing the whole concept we read till now.

Vipin said:   1 decade ago
Alternative method::

Let the minutes covered when d situation occurs = x
now,
(total degrees covered by minute hand) - (total degrees covered by hr hand)= (outer angle between 12 and 9) i.e.
6x - x/2 = 270

x=540/11 which is our ans. :)

Nisha lakshmi said:   5 years ago
BTW 9 and 10 the hand of the clock will be together at 9:45(min and hr hand coincides).
Since 55 min gained by min hand in 60 min.
Thus 1 min gained by min hand in 60/55 min.
Now 45 min gained by min hand in 60/55 * 45 = 540/11 min.

V.k said:   1 decade ago
Total distance the minute hand cover with respect to hour hand is 270'

And the relative speed is 5.5.

So the time to cover is,

270/5.5 = 540/11.

Chandresh said:   10 years ago
You can try this way also.

360 = 30(10)-(11/2)m.
360-300 = (11/2)m.
(60*2)/11 = m.
m = 120/11;

Now just do: 60-(120/11) = 540/11 = 49.1/11.

Krish said:   1 decade ago
Sakshi,

The question is between 9 and 10 both the hands must coincide,.

So for the minute hand to reach 9 it has to gain 45 minute spaces.

Sivanandhini chandrasekar said:   10 months ago
Formula :
Θ = |11M/2 - 30H|.
0⁰=|11M/2 - 30*9|.
= 11M/2 - 270.
0⁰+270⁰=11M/2.
270*2/11=M.
540/11=M.
M = 49 1/11.
(5)

Irfan Qureshi said:   6 years ago
Formula : (11/2)M - 30*H = 0.

We have to find min so put H and get M.

M=min.
H=Hour.
put the value and get the answer in Min.

Jeet said:   9 years ago
In Q6 at 7, they are 25 mins apart, but in this Q at 9 they are 45 mins apart, is the angle measured clockwise/ anti clockwise?

Pradeep said:   1 decade ago
Here we can use the formula:
theta=11(m)/2-30(h)
same direction means 0 degree; hour=9
180=11(m)/2-30(9)
m=49 1/11


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