Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 15)
15.
At what time between 9 and 10 o'clock will the hands of a watch be together?
Answer: Option
Explanation:
To be together between 9 and 10 o'clock, the minute hand has to gain 45 min. spaces.
55 min. spaces gained in 60 min.
| 45 min. spaces are gained in |  |
60 | x 45 |  min or 49 |
1 | min. |
| 55 | 11 |
 The hands are together at 49 |
1 | min. past 9. |
| 11 |
Discussion:
48 comments Page 2 of 5.
Goku said:
1 decade ago
Keep it simple friends! Just use this formula.
12/11 (minutes to be gained). See in the question between 9 to 10'o clock we know that at 9:45 the hands will coincide so 45 minutes is to be gained from 9 o'clock.
So 12/11* (45) =49 1/9 (Answer).
12/11 (minutes to be gained). See in the question between 9 to 10'o clock we know that at 9:45 the hands will coincide so 45 minutes is to be gained from 9 o'clock.
So 12/11* (45) =49 1/9 (Answer).
A k singh said:
1 decade ago
What master formula you are giving its not applicable to a single question we are doing. All the time its having negative sign error. I don't think so that is the master formula but can say this is confusing the whole concept we read till now.
Vipin said:
1 decade ago
Alternative method::
Let the minutes covered when d situation occurs = x
now,
(total degrees covered by minute hand) - (total degrees covered by hr hand)= (outer angle between 12 and 9) i.e.
6x - x/2 = 270
x=540/11 which is our ans. :)
Let the minutes covered when d situation occurs = x
now,
(total degrees covered by minute hand) - (total degrees covered by hr hand)= (outer angle between 12 and 9) i.e.
6x - x/2 = 270
x=540/11 which is our ans. :)
Nisha lakshmi said:
6 years ago
BTW 9 and 10 the hand of the clock will be together at 9:45(min and hr hand coincides).
Since 55 min gained by min hand in 60 min.
Thus 1 min gained by min hand in 60/55 min.
Now 45 min gained by min hand in 60/55 * 45 = 540/11 min.
Since 55 min gained by min hand in 60 min.
Thus 1 min gained by min hand in 60/55 min.
Now 45 min gained by min hand in 60/55 * 45 = 540/11 min.
V.k said:
1 decade ago
Total distance the minute hand cover with respect to hour hand is 270'
And the relative speed is 5.5.
So the time to cover is,
270/5.5 = 540/11.
And the relative speed is 5.5.
So the time to cover is,
270/5.5 = 540/11.
Chandresh said:
1 decade ago
You can try this way also.
360 = 30(10)-(11/2)m.
360-300 = (11/2)m.
(60*2)/11 = m.
m = 120/11;
Now just do: 60-(120/11) = 540/11 = 49.1/11.
360 = 30(10)-(11/2)m.
360-300 = (11/2)m.
(60*2)/11 = m.
m = 120/11;
Now just do: 60-(120/11) = 540/11 = 49.1/11.
Krish said:
1 decade ago
Sakshi,
The question is between 9 and 10 both the hands must coincide,.
So for the minute hand to reach 9 it has to gain 45 minute spaces.
The question is between 9 and 10 both the hands must coincide,.
So for the minute hand to reach 9 it has to gain 45 minute spaces.
Sivanandhini chandrasekar said:
2 years ago
Formula :
Θ = |11M/2 - 30H|.
0⁰=|11M/2 - 30*9|.
= 11M/2 - 270.
0⁰+270⁰=11M/2.
270*2/11=M.
540/11=M.
M = 49 1/11.
Θ = |11M/2 - 30H|.
0⁰=|11M/2 - 30*9|.
= 11M/2 - 270.
0⁰+270⁰=11M/2.
270*2/11=M.
540/11=M.
M = 49 1/11.
(6)
Irfan Qureshi said:
7 years ago
Formula : (11/2)M - 30*H = 0.
We have to find min so put H and get M.
M=min.
H=Hour.
put the value and get the answer in Min.
We have to find min so put H and get M.
M=min.
H=Hour.
put the value and get the answer in Min.
Jeet said:
1 decade ago
In Q6 at 7, they are 25 mins apart, but in this Q at 9 they are 45 mins apart, is the angle measured clockwise/ anti clockwise?
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