Aptitude - Clock - Discussion
Discussion Forum : Clock - General Questions (Q.No. 8)
8.
The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
Answer: Option
Explanation:
| Angle traced by hour hand in | 13 | hrs = | ![]() |
360 | x | 13 | ![]() |
° | = 130°. |
| 3 | 12 | 3 |
| Angle traced by min. hand in 20 min. = | ![]() |
360 | x 20 | ![]() |
° | = 120°. |
| 60 |
Required angle = (130 - 120)° = 10°.
Discussion:
80 comments Page 5 of 8.
Parimon said:
5 days ago
Thanks all for explaining it. @Deepti.
Aashish said:
1 decade ago
I agree with Saum. Can someone please clear our doubt?
Arko said:
1 decade ago
The formula is 30*h- (11/2) *m.
Nikhila said:
1 decade ago
Hey all.
We know that the minute hand is at 4 at 4. 20. We jst hav to calculate the angle moved by hour hand from 4 for 20 min.
For 60 min, Hour hand covers 360/12=30 degree.
For 20min, it covers 30*20/60= 10 degree. (Just cross multiply. ).
We know that the minute hand is at 4 at 4. 20. We jst hav to calculate the angle moved by hour hand from 4 for 20 min.
For 60 min, Hour hand covers 360/12=30 degree.
For 20min, it covers 30*20/60= 10 degree. (Just cross multiply. ).
Mohan said:
1 decade ago
To find angle take this formula.
Angle= ( (11/2) *min-30*hour).
If we get angle value as negative take that value as positive. That will be the answer.
Angle= ( (11/2) *min-30*hour).
If we get angle value as negative take that value as positive. That will be the answer.
Prasant said:
1 decade ago
60 parts by min hand = 5 parts by hr hand.
20 parts by min hand = (5/60) *20 = 1 2/3 part by hr hand.
1 part = 6 degree.
1 2/3 part = 10 degree.
20 parts by min hand = (5/60) *20 = 1 2/3 part by hr hand.
1 part = 6 degree.
1 2/3 part = 10 degree.
Raviteja said:
1 decade ago
Here is a simple formula to get an angel between hands..
30*[ Difference b/t hours and ( min /5) ]+ (min/2)
Take an example 4:20
30*[4~20/5]+(20/2)=0+10 = 10
30*[ Difference b/t hours and ( min /5) ]+ (min/2)
Take an example 4:20
30*[4~20/5]+(20/2)=0+10 = 10
Mouparna said:
1 decade ago
Thanks Prasad.........
Hemant said:
1 decade ago
We can also mark the ans by common sense..ie,
1. It is clear that the angle could not be 0.
2. Since the hour hand leads the min hand, and it will be in between 4 to 5, if the time will be 4.30, hour hand exactly in mid of 4 n 5, i.e 5min=30 degree, than half is 15 degree if the time would 4.30, but it is less than the 4.30, so angle will be slightly less than the 15 degree.
1. It is clear that the angle could not be 0.
2. Since the hour hand leads the min hand, and it will be in between 4 to 5, if the time will be 4.30, hour hand exactly in mid of 4 n 5, i.e 5min=30 degree, than half is 15 degree if the time would 4.30, but it is less than the 4.30, so angle will be slightly less than the 15 degree.
Javan said:
1 decade ago
Thanks anil..
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