# Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 8)
8.
The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
10°
20°
Explanation:

 Angle traced by hour hand in 13 hrs = 360 x 13 ° = 130°. 3 12 3

 Angle traced by min. hand in 20 min. = 360 x 20 ° = 120°. 60

Required angle = (130 - 120)° = 10°.

Discussion:
77 comments Page 1 of 8.

Aaditya Pant said:   1 year ago
None of this is required. I use a basic formula, which is the absolute value of 30H- 5.5m.
Therefore, Angle = (30x4) - (5.5x20).
= 120-110.
= 10 °.
(8)

Deepti said:   1 year ago
Formula ( 30×Hrs - 11/2min),
= 30 × 4 - 11/2 × 20.
= 120 - 110.
= 10°.
(6)

Omkar said:   4 years ago
Just use this formula.
A = 30 * H - 5.5 * M.
Where;
A = angle.
H = hour.
M = minutes.
(6)

Anil said:   3 years ago
For 1 min the Hr hand moves 0.5,
So, the angle between Hr and Min hand is =0,
Since Min Hand moves 20 mins. We have 20*0.5=10.
Therefore 0 + 10 = 10.
(4)

By common sense it is clear that in 20 minutes the minute hand will move 20*6=120degree and the hour hand will move20*(1/2)=10degree.
Clearly min hand will be at 20 and hour hand will be 10degree apart.
(1)

Omkar said:   3 years ago
Short trick for these ans.

Take a ratio of 4.20=1:5 then there is a formula, when ur ratio is 1:5 then, divide minutes by 2
i.e 20Ã·2 = 10.

Also when ratio is 1:8 then (minute-hours) * 2
Also for the ratio 1:3, = minute * 4+minute Ã·2
Ratio 1:10, θ = minute*2.5.
1:4then θ= minute*2.
1:6 θ = minute Ã·2.
(1)

Ansh Shukla said:   4 years ago
How 1-hour cover 30°?

(1)

Anuranan said:   5 years ago
It very simple.

1 Hour cover =30 °
So, 60 minutes cover 30 °.
1 minutes cover 30/60 -_1/2 °.
20 minutes cover 20 (1/2) °.
Equal to 10 °.
(1)

Premsai said:   9 years ago
I am not able to understand.
(1)

Greeshma said:   9 years ago
I think the formula you given (11M-60H)/2 is wrong, It is not coming can you explain it? For example the angle between the two hands at 6:00 it is giving wrong answer.