Aptitude - Clock - Discussion

Discussion Forum : Clock - General Questions (Q.No. 8)
8.
The angle between the minute hand and the hour hand of a clock when the time is 4.20, is:
10°
20°
Answer: Option
Explanation:

Angle traced by hour hand in 13 hrs = 360 x 13 ° = 130°.
3 12 3

Angle traced by min. hand in 20 min. = 360 x 20 ° = 120°.
60

Required angle = (130 - 120)° = 10°.

Discussion:
79 comments Page 8 of 8.

Greeshma said:   1 decade ago
I think the formula you given (11M-60H)/2 is wrong, It is not coming can you explain it? For example the angle between the two hands at 6:00 it is giving wrong answer.

Gaurav Verma said:   1 decade ago
We can write 4:20 in fractional form 4(20/60).
Means,
(60 *4 + 20)/60.

Equals,
13/3.

Jawahar.s said:   1 decade ago
360/12 *4 = 120.
360/60 *20 = 120.
120-120 = 0.

Anurag Nayak said:   1 decade ago
Start at 4 pm. minute hand has to travel 20 min.

We know,
5 min gain by hour hand in 1 hour/60 min.
?? min gain by hour hand in these 20 min.

5/60 * 20 = 5/3 min.

We know 5 min is 30 degree.
5/3 min is 30/3 = 10 degree. Simple.

Chaturbhuj Singh said:   1 decade ago
4:20 = 4 +20/60 = 4+1/3 = 13/3.

Ali Zohair Shah said:   1 decade ago
It is 4 degree.
Because hour hand moves 30 degree in 1hour.

So it is 1/3 hours passed so it rotates 10 degree.
Total angle of hours hand is 30*4+10 = 130 degree.

Minute hand moves 6 degree in 1 minute = 20*6 = 120 degree.
So 130-120 = 10 degree.

Navya said:   1 decade ago
In the above someone said apply direct formula that is: 11M - 60H/2.

Can this formula be applicable to all problems guys.

Explain please.

Praneeth said:   1 decade ago
Divide into 12 parts each division 30 deg. for hrs. hand for every min it moves by 1/2deg.

20 min = 20*1/2 = 10dg that's it.

Karthiga said:   1 decade ago
To Anil.

Will the formula be applicable to all the problems sir?


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