Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 3)
3.
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
Answer: Option
Explanation:
Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
Machines | 6 | : | 10 | ![]() |
:: 270 : x |
Time (in minutes) | 1 | : | 4 |
6 x 1 x x = 10 x 4 x 270
![]() |
(10 x 4 x 270) |
(6) |
x = 1800.
Discussion:
29 comments Page 1 of 3.
Ravi Teja P said:
1 decade ago
Let no.of machines - 'm', no.of bottles - 'b', no.of minutes(time) - 't'.
For this type of problems, first know what we have to find? here we have to find bottles i.e. 'b'.
Now, find out the relation of 'b' with other parameters 'm' and 't'.
If no.of machines increases, no.of bottles increases(direct proportion)
m & b.....(1) **Assume &-proportionality symbol**
If no.of minutes increases, no.of bottles increases(direct proportion)
t & b......(2)
From (1)&(2)
mt & b......(3)
=> (mt/b)=constant
=> (m1*t1)/b1=(m2*t2)/b2
=> (6*1)/270=(10*4)/x
=> x=1800.
For this type of problems, first know what we have to find? here we have to find bottles i.e. 'b'.
Now, find out the relation of 'b' with other parameters 'm' and 't'.
If no.of machines increases, no.of bottles increases(direct proportion)
m & b.....(1) **Assume &-proportionality symbol**
If no.of minutes increases, no.of bottles increases(direct proportion)
t & b......(2)
From (1)&(2)
mt & b......(3)
=> (mt/b)=constant
=> (m1*t1)/b1=(m2*t2)/b2
=> (6*1)/270=(10*4)/x
=> x=1800.
(1)
Bharath said:
1 decade ago
6 machines produces 270 bottles in 1 minute so first we check how many bottles 1 machine can produce in 1 minute.
i.e. 270/6=45 bottles in 1 minute.
1 machine can produce 45 bottles in 1 minute.
Now we will check how many bottles can be produced in 4 mints.
i.e. 45*4=180 bottles.
1 machine can produce 180 bottles in 4 minutes 10 machines can produce 1800 bottles in 10 minutes.
i.e. 270/6=45 bottles in 1 minute.
1 machine can produce 45 bottles in 1 minute.
Now we will check how many bottles can be produced in 4 mints.
i.e. 45*4=180 bottles.
1 machine can produce 180 bottles in 4 minutes 10 machines can produce 1800 bottles in 10 minutes.
Shiva kumar said:
8 years ago
@Nishant.
(num of machine) * time = work.
First given, 6M * 1min = 270.
Then 1 machine =270/6= 45.
Second step given 10m * 4 = work -->1).
We know 1MACHINE=45 PUT IN EQ -->1.
10 * 45 * 4 = 450 * 4 = 1800.
It's simple hope you understand.
(num of machine) * time = work.
First given, 6M * 1min = 270.
Then 1 machine =270/6= 45.
Second step given 10m * 4 = work -->1).
We know 1MACHINE=45 PUT IN EQ -->1.
10 * 45 * 4 = 450 * 4 = 1800.
It's simple hope you understand.
(1)
Eshita said:
4 years ago
Hello @Sandy.
Your doubt was how do we evaluate propotions.
So, if more and less are there or less and more are there it is indirect.
And if more and more are there or les and less are there it is direct proportion.
Hope it will helps.
Your doubt was how do we evaluate propotions.
So, if more and less are there or less and more are there it is indirect.
And if more and more are there or les and less are there it is direct proportion.
Hope it will helps.
Nishant said:
9 years ago
What kind of formula is this? they change formula whenever they want to. See the 1st and 3rd question. Both are same. Which formula is correct. They change the sequence of formula. Anybody help it, please.
(2)
Vishal Pathak said:
6 years ago
6 Machine ----- 1min ----- 270 bottle,
1 Machine ----- 1min ----- 270/6 bottle,
1 Machine ----- 4min ----- (270/6) * 4,
10 Machine ----- 4min ----- (270/6) * 4 * 10.
So, 1800 is the answer.
1 Machine ----- 1min ----- 270/6 bottle,
1 Machine ----- 4min ----- (270/6) * 4,
10 Machine ----- 4min ----- (270/6) * 4 * 10.
So, 1800 is the answer.
(28)
Lucas, DSM said:
9 years ago
When Direct Proportion: M1*D2*H1 = M2*D2*H2. I cannot understand the rule for calculating direct proportion amount especially using the formula. Please explain and provide worked example.
(1)
Nurun Nobi Khokon said:
7 years ago
6 Machine in 1 minute produce 270 units.
So, 1 machine in 1 minute produce 270/6 or 45 units.
So, 10 machines working 4 minutes produce = 45 x 10 x 4 or 1800 units.
So, 1 machine in 1 minute produce 270/6 or 45 units.
So, 10 machines working 4 minutes produce = 45 x 10 x 4 or 1800 units.
(2)
Nikhil said:
1 decade ago
1 machine can produce= 270/6=45 bottles (in 1 minute)
10 machines can produce=10*45=450 bottles(in 1 minute)
so in 4 minutes no of bottles produced= 450*4=1800
10 machines can produce=10*45=450 bottles(in 1 minute)
so in 4 minutes no of bottles produced= 450*4=1800
Sunraj said:
1 decade ago
6 M/C = 270 Bottles/min.
1 M/C = 270/6 Bottles/min = 45 Bottles/min.
10 M/C = 45*10 = 450 Bottles/min.
So, in 4 min,
Number of Bottles = 450*4 = -1800.
1 M/C = 270/6 Bottles/min = 45 Bottles/min.
10 M/C = 45*10 = 450 Bottles/min.
So, in 4 min,
Number of Bottles = 450*4 = -1800.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers