Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 3)
3.
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?
Answer: Option
Explanation:
Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
| Machines | 6 | : | 10 |  |
:: 270 : x |
| Time (in minutes) | 1 | : | 4 |
6 x 1 x x = 10 x 4 x 270
 x = |
(10 x 4 x 270) |
| (6) |
x = 1800.
Discussion:
29 comments Page 1 of 3.
Souji said:
1 decade ago
Total bottles 270 for 6 machines in 1 minute...
for each machine...=270/6=45bottles...in 1mnt
for 10 bottles......45*10=450*4=1800..in 4mnts
for each machine...=270/6=45bottles...in 1mnt
for 10 bottles......45*10=450*4=1800..in 4mnts
Vino said:
1 decade ago
Explain in detail this direct proportion.
Sandy said:
1 decade ago
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
Please anybody explain me how evaluate proportions?
More minutes, More bottles (Direct Proportion)
Please anybody explain me how evaluate proportions?
Umesh said:
1 decade ago
Production in 6 minutes = 270
Production in 01 minutes = 270/6
Production in 40 minutes = 270/6 *40 = 1800.
Production in 01 minutes = 270/6
Production in 40 minutes = 270/6 *40 = 1800.
KAPIL said:
1 decade ago
M1*H1/W1 = M2*H2/W2
6*1/270 = 10*4/W2
W2= 1800
6*1/270 = 10*4/W2
W2= 1800
Nikhil said:
1 decade ago
1 machine can produce= 270/6=45 bottles (in 1 minute)
10 machines can produce=10*45=450 bottles(in 1 minute)
so in 4 minutes no of bottles produced= 450*4=1800
10 machines can produce=10*45=450 bottles(in 1 minute)
so in 4 minutes no of bottles produced= 450*4=1800
Saurabh dwivedi said:
1 decade ago
Well explanation given by sauji & nikhil.
Nids said:
1 decade ago
Simple way
6 - 270
10 - ?
= 450 bottles
Now 450 in 1 minute so in 4 minutes= 1800
6 - 270
10 - ?
= 450 bottles
Now 450 in 1 minute so in 4 minutes= 1800
Ravi Teja P said:
1 decade ago
Let no.of machines - 'm', no.of bottles - 'b', no.of minutes(time) - 't'.
For this type of problems, first know what we have to find? here we have to find bottles i.e. 'b'.
Now, find out the relation of 'b' with other parameters 'm' and 't'.
If no.of machines increases, no.of bottles increases(direct proportion)
m & b.....(1) **Assume &-proportionality symbol**
If no.of minutes increases, no.of bottles increases(direct proportion)
t & b......(2)
From (1)&(2)
mt & b......(3)
=> (mt/b)=constant
=> (m1*t1)/b1=(m2*t2)/b2
=> (6*1)/270=(10*4)/x
=> x=1800.
For this type of problems, first know what we have to find? here we have to find bottles i.e. 'b'.
Now, find out the relation of 'b' with other parameters 'm' and 't'.
If no.of machines increases, no.of bottles increases(direct proportion)
m & b.....(1) **Assume &-proportionality symbol**
If no.of minutes increases, no.of bottles increases(direct proportion)
t & b......(2)
From (1)&(2)
mt & b......(3)
=> (mt/b)=constant
=> (m1*t1)/b1=(m2*t2)/b2
=> (6*1)/270=(10*4)/x
=> x=1800.
(1)
Javeed said:
1 decade ago
@ravi Teja : Super Explanation
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