Aptitude - Chain Rule - Discussion
Discussion Forum : Chain Rule - General Questions (Q.No. 4)
4.
A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:
Answer: Option
Explanation:
After 10 days : 150 men had food for 35 days.
Suppose 125 men had food for x days.
Now, Less men, More days (Indirect Proportion)
125 : 150 :: 35 : x 
125 x x = 150 x 35
 x = |
150 x 35 |
| 125 |
x = 42.
Discussion:
82 comments Page 8 of 9.
Durga k said:
5 years ago
@Rahul.
Thanks for the explanation.
Thanks for the explanation.
Miwa said:
5 years ago
25 men left after 10 days.
So, let's assume we save their food for the next 35 days and keep that food aside.
That should be equal to 25 * 35 = 875.
After 45 days we bring that food out.
Now, there are 125 men left in the fort.
So, 125 men will be consuming (food that was not consumed)25 * 5 times the food.
For the each day i.e 875 ÷ 125 = 7.
Hence now total days = 35 + 7 = 42.
So, let's assume we save their food for the next 35 days and keep that food aside.
That should be equal to 25 * 35 = 875.
After 45 days we bring that food out.
Now, there are 125 men left in the fort.
So, 125 men will be consuming (food that was not consumed)25 * 5 times the food.
For the each day i.e 875 ÷ 125 = 7.
Hence now total days = 35 + 7 = 42.
Sanjay said:
4 years ago
@Vikas.
Nice explanation.
Nice explanation.
Rhushikesh said:
4 years ago
@Vikas.
Nice explanation. Thanks.
Nice explanation. Thanks.
Nikhil said:
4 years ago
Food for 25 men for 35 would be left which could be consumed by other 125 (this would be devided or distributed in these people) so the equation becomes,
=> 25*35/125.
=7.
So total day the food lasts long =35+7=42.
=> 25*35/125.
=7.
So total day the food lasts long =35+7=42.
Kelzang Gyeltshen said:
4 years ago
Lets assume 1 kg of food is eaten by each person.
Total quantity of food =150 x 45
= 6750kg.
Quantity of food finished in ten days by 150 men = 150 x 10
= 1500kg.
Amount of food remained = 6750 - 1500.
= 5250kg.
Therefore, number of days the remaining food can be eaten by 125 people
= 5250/125 = 42 days.
Total quantity of food =150 x 45
= 6750kg.
Quantity of food finished in ten days by 150 men = 150 x 10
= 1500kg.
Amount of food remained = 6750 - 1500.
= 5250kg.
Therefore, number of days the remaining food can be eaten by 125 people
= 5250/125 = 42 days.
(17)
Kavyanshu Singh said:
4 years ago
Thanks @Vikas.
(1)
Sankalp said:
4 years ago
150 * (45-10) = (150-25) * X,
150 * 35 = 125 * X,
X = 150 * 35 ÷ 125 ,
X = 42.
150 * 35 = 125 * X,
X = 150 * 35 ÷ 125 ,
X = 42.
(5)
Ashish said:
4 years ago
Nice, Thanks @Vikas.
(1)
Sushil said:
3 years ago
Case first;
150 mens, 45days.
Food quantity=150*45=6750 units.
After 10days Food quantity was reduced,
=> 150*10 = 1500 unit.
Balance quantity,
6750-1500=5150 Unit.
Case second:
125 men, assume - z days, Balance quantity-
5150 Unit.
Days-Z=5150/125=42.
150 mens, 45days.
Food quantity=150*45=6750 units.
After 10days Food quantity was reduced,
=> 150*10 = 1500 unit.
Balance quantity,
6750-1500=5150 Unit.
Case second:
125 men, assume - z days, Balance quantity-
5150 Unit.
Days-Z=5150/125=42.
(63)
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