Aptitude - Chain Rule - Discussion

Case first;
150 mens, 45days.
Food quantity=150*45=6750 units.

After 10days Food quantity was reduced,
=> 150*10 = 1500 unit.

Balance quantity,
6750-1500=5150 Unit.

Case second:
125 men, assume - z days, Balance quantity-
5150 Unit.
Days-Z=5150/125=42.

Lets assume 1 kg of food is eaten by each person.

Total quantity of food =150 x 45
= 6750kg.

Quantity of food finished in ten days by 150 men = 150 x 10
= 1500kg.

Amount of food remained = 6750 - 1500.
= 5250kg.

Therefore, number of days the remaining food can be eaten by 125 people
= 5250/125 = 42 days.

Hi All,

I was little puzzled the way they have solved the question. I hv been average students so high funda I cant understand. Simple and natural way to do it is as follows:

Total food available=150*45
They all consume food for 10 days, food consumed in 10 days=150*10
Food left after 10 days=150*45-150*10
For how many days 125 people can eat this food=
(150*45-150*10)/125
=42

I hope that was simple to understand

150 * (45-10) = (150-25) * X,
150 * 35 = 125 * X,
X = 150 * 35 ÷ 125 ,
X = 42.

Hi,

I always confused to solve these type of problems. Please help me, how to solve these type of problems in very efficient way.

Nice, Thanks @Vikas.

Thanks @Vikas.

In this kind of problems always consider.

Amount of food= no. of days * no. of men.
Food amount will always be constant, hence equate the conditions accordingly.

Firstly,

Amount of food = 150 * 45
After 10 days, amount of food = 150*10
Amount of food left after 10 days = 150*(45-10) = 150 * 35
This food amount will be consumed by 150-25 = 125 men in 'x' days say,
So,

150*35 = 125*x,
x = 150 * 35/ 125,
x = 42 days.

I hope this solution would make problems of this type easier to solve.

A ship has food provision for 300 people for 30 days. If 200 more people join the ship, how long will the provisional last?

Can anyone solve this?

Why can't the equation be 125 * 150 = 45 * x?