Aptitude - Chain Rule - Discussion

Thanks @Vikas.

Thanks @Vikas.

@Durga.

Thanks for the explanation.

A ship has food provision for 300 people for 30 days. If 200 more people join the ship, how long will the provisional last?

Can anyone solve this?

Let the required number of days be 'x'.
150*45=(150*10)+(125*x),
Hence, x=42.

Thanks @Vikash.

In this kind of problems always consider.

Amount of food= no. of days * no. of men.
Food amount will always be constant, hence equate the conditions accordingly.

Firstly,

Amount of food = 150 * 45
After 10 days, amount of food = 150*10
Amount of food left after 10 days = 150*(45-10) = 150 * 35
This food amount will be consumed by 150-25 = 125 men in 'x' days say,
So,

150*35 = 125*x,
x = 150 * 35/ 125,
x = 42 days.

I hope this solution would make problems of this type easier to solve.

25 persons food remain for next 35 days.
125 person can eat the above food fro next 7 days.

ie 25*35/125=7.
so 35 days + 7 days=42 days.

@Sameenamhd.

Your question is an inversely proportionate one without any condition.

If 9 people eat for 26 days.
Then 13(9+4) will eat for x.
9:13=x:26 then x=18 days.

Let the total food be x.

150 men ate x food for 45 days i.e. 150 men ate x food for first 10 days and rest 35 days

But when 25 men left after 10 days the food left was only what 150 men would eat for the rest 35 days as mentioned above.

Hence 125 men only had food that 150 men would have eaten for rest 35 days.

Thus,
150:125= days:35 ( inversely proportionate)
Days = 150*35/125=42.