Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 9 of 26.
Vijay said:
1 decade ago
365 day = 1 year, day364/7days = 54weeks, balance 1 day that will be conce considered as ODD days.
If it is leap year total no of days for = 366, 364/7 = 54 weeks balnce 2 days.
If it is leap year total no of days for = 366, 364/7 = 54 weeks balnce 2 days.
Satishmohan said:
1 decade ago
Sridhar my quetion for you how you wrote century table we have to remember that or else is there any calculation but your expalanation so nice I have that doubt only, so please clarify that and before 1700 how you know value ?
Abhinav said:
1 decade ago
It is Thursday on 25th of September. What day will it be on the 25th of October in the same year?
Subhashree said:
1 decade ago
@Sridhar, how we know the centuries table value or months table value?
Vipanchi said:
1 decade ago
Hi could you please explain clearly formula to find the day of the week.
Kundan K said:
1 decade ago
Hi friends,
There are 52 weeks in a year.And there are 7 days a week.So, the closest factor of 7 is 49.And 52-49=3.So after 49 days again there will be Sunday.So,add 3 days to Sunday that is Wednesday.Now similarly continuously add 3 days for 4 times as there is difference of 4 years between 2010 & 2006.
Therefore the ans is "FRIDAY".
There are 52 weeks in a year.And there are 7 days a week.So, the closest factor of 7 is 49.And 52-49=3.So after 49 days again there will be Sunday.So,add 3 days to Sunday that is Wednesday.Now similarly continuously add 3 days for 4 times as there is difference of 4 years between 2010 & 2006.
Therefore the ans is "FRIDAY".
Chandu said:
1 decade ago
Thanks sundar
Intaj said:
1 decade ago
Hi, you can do it easily follow my shortcut rule :-
jan = (1) = 3 jan = 31/7 = remain = 3
feb = (2)= 0 feb= 28/7 = remain = 0
march = (3)= 3
april = (4)= 2 april = 30/7 = reminder = 2
may = (5) = 3
june = (6) = 2
july = (7) =3 ====================================
aug = (8)= 3 (1 , 3, 5, 7, 8, 10, 12) = 3
sept = (9)= 2 ( 4, 6, 9, 11) = 2
oct = (10)= 3 2= 0 (Feb)
nov = (11) = 2
dec = (12) = 3 JUST REMEMBER ABOVE
jan = (1) = 3 jan = 31/7 = remain = 3
feb = (2)= 0 feb= 28/7 = remain = 0
march = (3)= 3
april = (4)= 2 april = 30/7 = reminder = 2
may = (5) = 3
june = (6) = 2
july = (7) =3 ====================================
aug = (8)= 3 (1 , 3, 5, 7, 8, 10, 12) = 3
sept = (9)= 2 ( 4, 6, 9, 11) = 2
oct = (10)= 3 2= 0 (Feb)
nov = (11) = 2
dec = (12) = 3 JUST REMEMBER ABOVE
Arkright said:
1 decade ago
Why do you divide with is it 4 or 7 to get a leap /ordinary year am confused some of you using 7 while others 4. Please explain?
Manish tiwari said:
1 decade ago
Thanks pavitra. Really good dear.
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