Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
261 comments Page 26 of 27.

Desu said:   7 years ago
On a fix particular date, as the year increases by one unit, the day also increases by one unit, Except for leap year where the day is increased by two units.

So coming to the problem:

On particular date 1 Jan.
Day- sun and year-2006.

So on increasing year by one unit.
Year - Day
2007 -.Monday.
2008. - Tuesday.
2009 - Thursday (when leap year is increased by one unit days Will be increased by two units)
2010 - Friday.

Rashi Thakur said:   7 years ago
How can we find that 1996 is a leap year?

Saket said:   7 years ago
3 April 2005.
6 August 2010.
5 December 2013.
15 August ?

Monika said:   7 years ago
How many Sundays are there in year if 1st December in that year is on Sunday?

Ganesh said:   7 years ago
November 25, 1950 was Saturday what day was November 2016?

Deepika said:   7 years ago
If the first day of 1987 is Thursday, then what will be the last day of the year 1987?

Dame said:   6 years ago
We can find odd days by year divided by 4.

Monalisha said:   6 years ago
Good explanation Thanks. @Sundar.

Vibisha said:   6 years ago
How many odd days in 1800? Explain please.

Surajmatte said:   6 years ago
Leap year means 29 days in Feb.

Year whole divided by 4.

Next year of a leap is 2 days shift. Ex 1st Jan 2017 Sunday then 1st Jan 2021 Friday. 2020 is a leap year because 4 divided by 2020 or any year. After a leap year 2 days shift.


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