Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 26 of 26.
Monika said:
6 years ago
How many Sundays are there in year if 1st December in that year is on Sunday?
Ganesh said:
5 years ago
November 25, 1950 was Saturday what day was November 2016?
Deepika said:
5 years ago
If the first day of 1987 is Thursday, then what will be the last day of the year 1987?
Dame said:
5 years ago
We can find odd days by year divided by 4.
Monalisha said:
5 years ago
Good explanation Thanks. @Sundar.
Vibisha said:
5 years ago
How many odd days in 1800? Explain please.
Surajmatte said:
5 years ago
Leap year means 29 days in Feb.
Year whole divided by 4.
Next year of a leap is 2 days shift. Ex 1st Jan 2017 Sunday then 1st Jan 2021 Friday. 2020 is a leap year because 4 divided by 2020 or any year. After a leap year 2 days shift.
Year whole divided by 4.
Next year of a leap is 2 days shift. Ex 1st Jan 2017 Sunday then 1st Jan 2021 Friday. 2020 is a leap year because 4 divided by 2020 or any year. After a leap year 2 days shift.
Anciya said:
4 years ago
Odd days in 1800 = 1800/7.
Thus we get quotient 52 and remainder 1.
So, the number of odd days in 1800 = 1 odd day.
Thus we get quotient 52 and remainder 1.
So, the number of odd days in 1800 = 1 odd day.
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