Aptitude - Calendar - Discussion

1 ordinary year = 365days = 52weeks + 1day
so, each ordinary year has 1 odd day.

1 leap year = 366 days = 52 weeks + 2 days (since 52 weeks=364days so, in leap year , to get 366 days we add 2 in 364)
so, each leap year has 2 odd days


100 years = 76 ordinary years + 24 leap years
= 76 multiply with its odd day i.e 1 + 24 multiply with its odd days i.e 2
= 76 + 48
=124 odd days

This means that every 100 years contain 124 odd days.

Pavithra very wrong method. How can you calculate 16th july 1776 ?

Yes Arpana Pavithra's formula is somewhere wrong.

Nice sundar.

We want what day is jan 1,2010 for that

2000+9+jan1;
0+(9/4)+1
=(2+7)+1(2=leap year,7=non leap year)
=(2*2+7*1)+1
=4+7+1=12/7=5 odd days
= Friday

Thanks pavithra and sundar.

I would like to know , how many leap years are there in 99 years and 100 years.

i.e How to calculate number of leap years from 'n' number of years ?

I too want to know the same.

Centuries Table

1700-1799 4
1800-1899 2
1900-1999 0
2000-2099 6
2100-2199 4
2200-2299 2
2300-2399 0
2400-2499 6
2500-2599 4
2600-2699 2

Months Table:

January 0 (in leap year 6)
February 3 (in leap year 2)
March 3
April 6
May 1
June 4
July 6
August 2
September 5
October 0
November 3
December 5
Days Table:

Sunday 0
Monday 1
Tuesday 2
Wednesday 3
Thursday 4
Friday 5
Saturday 6


For example

April 24,1982.

1. Look up the 1900s in the centuries table: 0
2. Note the last two digits of the year: 82
3. Divide the 82 by 4: 82/4 = 20.5 and drop the fractionalpart: 20
4. Look up April in the months table: 6
5. Add all numbers from steps 1-4 to the day of the month (in this case, 24): 0+82+20+6+24=132.
6. Divide the sum from step 5 by 7 and find the remainder: 132/7=18 remainder 6
7. Find the remainder in the days table: 6=Saturday.

Thanks pavithra

Sridhar my quetion for you how you wrote century table we have to remember that or else is there any calculation but your expalanation so nice I have that doubt only, so please clarify that and before 1700 how you know value ?