Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
258 comments Page 6 of 26.

Boomathi said:   1 decade ago
Please tell how do we know the leap year?

Latha said:   1 decade ago
@Boomathi.

We know the given year is leap year or not, that year is divided by 4. That number (year) does not give any remainder that year is called leap year.

Saamy said:   1 decade ago
How there are 24 leaf years there in 100 years.

Anyone please explain.

Pavithra said:   1 decade ago
Hi there is a formula for this type of problem.

Plz memorize this

jan=1
feb=4
mar=4
apr=0
may=2
jun=5
jul=0
aug=3
sep=6
oct=1
nov=4
dec=6

days:
s=1
m=2
t=3
w=4
th=5
f=6
sat=7 or 0

formula=day+mon no.+(x-1900)+(x-1900)/4
x= the year we have to calculate

Eg:
16-may-2011

for=16+2+(2011-1900)+(2011-1900)/4
=16+2+111+111/4
=16+2+111+27
  (here we should not take the no behind decimal i.e 111/4=27.75)
=156

156/7=2(reminder)

mon =2

Seetharaman said:   1 decade ago
Thanks pavithra.

Suman said:   1 decade ago
Many many thanx...Pavithra

Kamal said:   1 decade ago
Pavithra can you apply you are concept for this date?.

1st Jan 2008.

If please explain it with steps.

Kamal said:   1 decade ago
Vijay can we do the same calculations for years like 2000, 1990, 1980 ?

Sonu navgotri said:   1 decade ago
For non-leap year odd number = 1 .

For leap year odd number = 2.

DG1234 said:   1 decade ago
This formula does not work on leap year. Pavithra..I am so sorry


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