Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 5 of 26.
Hitesh Handke said:
1 week ago
365 + 366 + 365 + 365 + 1 = 1461.
1461%7 = 5 and 5 it means Friday.
1461%7 = 5 and 5 it means Friday.
(1)
Goutham said:
2 decades ago
What is odd days?
Alaguvel.c said:
2 decades ago
How to find odd days?
Rajeswari said:
2 decades ago
Nice Sundar.
Bhupendra said:
1 decade ago
31 dec 2005 = Saturday
365/7 = 52+1/7
2006= 1 odd day
2007= 1 odd day
2008=> 366/7 = 52+ 2/7=> 2 odd day
then 31 Dec 2008= Thursday
and 1 Jan 2009 = Friday.
365/7 = 52+1/7
2006= 1 odd day
2007= 1 odd day
2008=> 366/7 = 52+ 2/7=> 2 odd day
then 31 Dec 2008= Thursday
and 1 Jan 2009 = Friday.
Nilesh said:
1 decade ago
How do we know leap year of that specific year?
Manu said:
1 decade ago
Everytime the odd days are considered from sunday onwards i.e.,if there are are 0 odd days then we take the day as sunday and the count follows likewise
Shaunak said:
1 decade ago
@veer singh pal:your answer is partially correct.for years like 1600,1700,1800,1900,2000 etc,we need to divide by 400.for other nos.,it needs to be a multiple of 4.
Arun Anoop M said:
1 decade ago
Thanks vijaya
100=24 leap yr+[100-24]ordinary days
=[24*2]+76
=124
my way is
124=17weeks+5 ordinary days
So answer is 5.
But your way is very easy
124/7=5(remainder).
100=24 leap yr+[100-24]ordinary days
=[24*2]+76
=124
my way is
124=17weeks+5 ordinary days
So answer is 5.
But your way is very easy
124/7=5(remainder).
Priyavel said:
1 decade ago
Hai Nilesh.
We divide year by 400. If remainder comes 0 means that year is leap year.
We divide year by 400. If remainder comes 0 means that year is leap year.
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