Aptitude - Calendar - Discussion

Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Sunday
Saturday
Friday
Wednesday
Answer: Option
Explanation:

On 31st December, 2005 it was Saturday.

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday.

Discussion:
258 comments Page 5 of 26.

Madhurima said:   5 years ago
Hi, how does adding odd no. Of days give us the exact same date for the next year? for EG if 1st of Jan was Monday then do we need to add 5 to Monday? Please explain to me.
(1)

Sony said:   4 years ago
@Sumanth Geras.

If x is less than 1900. We get a negative value then what we do?

Could you please explain?
(1)

Goutham said:   2 decades ago
What is odd days?

Alaguvel.c said:   2 decades ago
How to find odd days?

Rajeswari said:   2 decades ago
Nice Sundar.

Bhupendra said:   2 decades ago
31 dec 2005 = Saturday
365/7 = 52+1/7
2006= 1 odd day
2007= 1 odd day
2008=> 366/7 = 52+ 2/7=> 2 odd day
then 31 Dec 2008= Thursday
and 1 Jan 2009 = Friday.

Nilesh said:   2 decades ago
How do we know leap year of that specific year?

Manu said:   1 decade ago
Everytime the odd days are considered from sunday onwards i.e.,if there are are 0 odd days then we take the day as sunday and the count follows likewise

Shaunak said:   1 decade ago
@veer singh pal:your answer is partially correct.for years like 1600,1700,1800,1900,2000 etc,we need to divide by 400.for other nos.,it needs to be a multiple of 4.

Arun Anoop M said:   1 decade ago
Thanks vijaya

100=24 leap yr+[100-24]ordinary days
=[24*2]+76
=124
my way is
124=17weeks+5 ordinary days
So answer is 5.

But your way is very easy
124/7=5(remainder).


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