Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
259 comments Page 13 of 26.
Naman Rai said:
1 decade ago
Odd days came as 5 so it should be Friday not Thursday. We take Sunday as 0. So if we start it from Sunday then till the counting of 5 it should come as Friday.
Sri said:
1 decade ago
How you got 24 leap years in 100 years ?
PRABHUCHANDU said:
1 decade ago
Centuries can be remembered like this :
1600-1699->6.
1700-1799->4.
1800-1899->2.
1900-1999->0.
2000-2099->6.
2100-2199->4.
2200-2299->2.
2300-2399->0.
.
.
.
.
.
.
This will continue.
1600-1699->6.
1700-1799->4.
1800-1899->2.
1900-1999->0.
2000-2099->6.
2100-2199->4.
2200-2299->2.
2300-2399->0.
.
.
.
.
.
.
This will continue.
Venkatesh said:
1 decade ago
How to find 31st December 2005 is Saturday?
Pawan Bejawada said:
1 decade ago
365/7 In this you have to consider reminder.
Neha said:
1 decade ago
How to calculate odd days?
Vinodh Guvalla said:
1 decade ago
This is easy explanation by @Narendra.
Sri said:
1 decade ago
If 1st Jan is a Sunday then find the number of Sundays in that year?
Jenny said:
1 decade ago
2006/4, 2007/4, 2008/4, 2009/4 if remainder will zero that is the leap year.
Mustaq said:
1 decade ago
1 year = 365 days and 8 hours.
So after 3 year = 3*8 = 24 hours = 1 days.
So after 3 year = 3*8 = 24 hours = 1 days.
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