Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 1)
1.
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?
Answer: Option
Explanation:
On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
Discussion:
258 comments Page 13 of 26.
PRABHUCHANDU said:
1 decade ago
Centuries can be remembered like this :
1600-1699->6.
1700-1799->4.
1800-1899->2.
1900-1999->0.
2000-2099->6.
2100-2199->4.
2200-2299->2.
2300-2399->0.
.
.
.
.
.
.
This will continue.
1600-1699->6.
1700-1799->4.
1800-1899->2.
1900-1999->0.
2000-2099->6.
2100-2199->4.
2200-2299->2.
2300-2399->0.
.
.
.
.
.
.
This will continue.
Venkatesh said:
1 decade ago
How to find 31st December 2005 is Saturday?
Pawan Bejawada said:
1 decade ago
365/7 In this you have to consider reminder.
Neha said:
1 decade ago
How to calculate odd days?
Vinodh Guvalla said:
1 decade ago
This is easy explanation by @Narendra.
Sri said:
1 decade ago
If 1st Jan is a Sunday then find the number of Sundays in that year?
Jenny said:
1 decade ago
2006/4, 2007/4, 2008/4, 2009/4 if remainder will zero that is the leap year.
Mustaq said:
1 decade ago
1 year = 365 days and 8 hours.
So after 3 year = 3*8 = 24 hours = 1 days.
So after 3 year = 3*8 = 24 hours = 1 days.
Priya Gaikwad said:
1 decade ago
1 jan 2006 = Sunday count 1 .
1 jan 2007 = Monday count 1.
1 jan 2008 = Tuesday count 1.
1 jan 2009 = Thursday count 2 because 2008 is leap year(2008/4=0).
1 jan 2010 = Friday. Req. answer.
1 jan 2007 = Monday count 1.
1 jan 2008 = Tuesday count 1.
1 jan 2009 = Thursday count 2 because 2008 is leap year(2008/4=0).
1 jan 2010 = Friday. Req. answer.
Prabu said:
1 decade ago
If any shortcut to solve this problem with in 1 min.
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