Aptitude - Calendar - Discussion

Eg: Today is 1st Monday, so after 7 days i.e. 8th is Monday so
From the given question: Today is Monday after 61 days it will
be Friday.

Sol: In 61
8*7=56 i.e. 57th is Monday
58 --- tue
59 --- wed
60 ---- thursday
61 ----- Friday

Today is Monday Each day of the week is repeated after 7 days.

So fist day and 8th day is same.

So Today is Monday mean 56th day is Monday.

So answer is Saturday (process:- 8*7=56, 56th day is common ga Monday:, so 57th:-the, 58:-wen, 59:-thu, 60:-fri, 61:-sat).

Monday = 1 odd day.

61 days = (8 weeks + 5 odd days).

= 5 odd days.

Total odds = 1 + 5 odd days.

= 6.

Number 6 mentions Saturday.

7*9=63-2=61
so after 61 days it will be saturday

Another question to further explain the above statement

What will be day after 366 says(keeping today as monday)??
subtracting it from 392.
392-366=26.
26/7=3.5/7( where 3 is quotient.
5 is remainder.
7 is divisor.)
now moving back 5 days (because of remainder).
it will be thursday.
another way to calcultae thursday.
as 7*4=28
but the diff is 26
28-26=2
moving ahead(instead of backward) from monday,it will tuesday first then wednesday but the third day will be thusday so we add
2 days to manday and the result will be the third day.

I hope it works.

Its upto to your choice what you choose(backward or ahead).

Ajay, thanks dear. , it's really a good & easy solution.

Deepa & ramya you both are right.

Sanju... its a very good solution realy

Any equations for solving this problem?

For 2006th year how we can take the odd days for 2000=?

Like 1600=0, 400=0.