Aptitude - Calendar - Discussion

Monday = 1, add 61 to it,
1 + 61 = 62/7.

we get
quotient: 8
Remainder : 6.

So, 6 means Saturday.

61 ÷7 = Take reminder will be 5,
So it's on Monday + 5days,
Monday + Tuesday, Wednesday, Thursday, Friday, Saturday.

61 ÷7 = Take reminder will be 5,
So it's on Monday + 5days,
Monday + Tuesday, Wednesday, Thursday, Friday, Saturday.

It's 61/7 = 5(rem).

From Monday, 5 days past so it is Saturday.

61 + monday = 62 days.
62/7 = 56 days(8 week) + 6 odd days.

Ans - Saturday.

We can use this;
Monday - 1.
Tuesday - 2.
Wednesday - 3.
Thursday - 4.
Friday - 5.
Saturday - 6.
Sunday - 0.

Find the odd days in 61 days.
61÷7,remainder = 5.
5 odd days so, Monday + 5 = Saturday.

61 days= 8 weeks + 5 days.
= 5 odd days.

Since Monday= 1 odd day,
= (1+5) odd days,
= 6 odd days.


Monday - 1
Tuesday - 2
Wednesday - 3
Thursday - 4
Friday - 5
Saturday - 6
Sunday - 0

So, the answer is Saturday.

@Ajay.

How to take odd days? Please explain.

@All.

Here, is the solution.

Today is considered as Monday.
61th day=?
a week has 7 days..
there are 8 weeks, 7 days in 61.
8*7=56.

The 56th day must be the same Monday.
56+remaining days from 61.
(ie)56+(61-56).
=56+5.
56(mon) + 5(tue + wed + thur + fri and the fifth day is Saturday)
so, the answer is Saturday.

Last two digits of year =20 (2020).

Divide it by 4 =5(quotient).

Take the date (the date that you are working this problem) =3 since am doing it on this date...
Month = 0 (0,3,3,6,1,4,6,2,5,0,3,5) October falls for number zero.

Year =6 (1600-1699=6), 1700-1799=4, 1800-1899=2, 1900-1999=0, 2000-2099=6.
Add all = that will give us 34.
Divide it by 7(days in a week).
Take reminder =34/7 remainder is 6.
Sun = 0
Mon = 1
Tue = 2
Wed = 3
Thu = 4
Fri = 5
Sat= 6.

So, the Answer here is Saturday.