Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 6 of 22.
John said:
1 decade ago
Its wrong the 2006-1900 is 106.
Praveena said:
1 decade ago
How it possible 2006-1900=16 do you explain.
G.M.L.GENATUS said:
1 decade ago
Every 400 years we consider as 0.
So 1200,1600,2000,2400 years take it as 0 value.
So 1200,1600,2000,2400 years take it as 0 value.
Kanakam said:
1 decade ago
How it possible 2006-1900=16 ........?
Ankita said:
1 decade ago
Why we have taken 1600 and 400 years only ? why not other year?
Ankita said:
1 decade ago
Why there is 1900 in above mentioned explanation?
Prajakta said:
1 decade ago
Nice Solution Deena...
Revathi said:
1 decade ago
Pavithra your example is wrong. 2006-1900=106 its not 16.
Yasar said:
1 decade ago
Please explain how the odd days of 400 and 1600 are 0 and the odd days of 300 is 15.
Priya said:
1 decade ago
Yes revathi I'm agree with you. Pavithra your example is wrong.
2006-1900=106 its not 16. If ok can you explain.
2006-1900=106 its not 16. If ok can you explain.
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