Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 5 of 22.
Sathiyaraj said:
9 years ago
Assume, 01-01-01 be a Monday,
So, 2006/4 = 501 leap years + 2 days,
501/7 = 71 weeks + 4 days,
So, 31-12-2005 ends with Saturday (4 + 2 days = 6),
Hence, 01-01-2006 starts on Sunday,
Jan 31+ Feb 28 + Mar 31+ Apr 30 + May 28 = 148 days,
148/7 = 21 weeks + 1 days,
2005 ends on Saturday + 1 = Sunday,
So 28 May 2006 was Sunday.
So, 2006/4 = 501 leap years + 2 days,
501/7 = 71 weeks + 4 days,
So, 31-12-2005 ends with Saturday (4 + 2 days = 6),
Hence, 01-01-2006 starts on Sunday,
Jan 31+ Feb 28 + Mar 31+ Apr 30 + May 28 = 148 days,
148/7 = 21 weeks + 1 days,
2005 ends on Saturday + 1 = Sunday,
So 28 May 2006 was Sunday.
Kevin said:
9 years ago
Applying doomsday method is the best thing in this type of problems.
Doomsday for a year= (year/12) + Remainder (year/12) + rem (year/12/4) : (year is last two digits).
Last day of Feb = 4 april (4/4); 6 june (6/6); 8 aug (8/8); 10 oct (10/10).
ANCHOR = WEDNESDAY for 1900 - 1999.
ANCHOR = TUESDAY for 2000 - 2999.
Doomsday for a year= (year/12) + Remainder (year/12) + rem (year/12/4) : (year is last two digits).
Last day of Feb = 4 april (4/4); 6 june (6/6); 8 aug (8/8); 10 oct (10/10).
ANCHOR = WEDNESDAY for 1900 - 1999.
ANCHOR = TUESDAY for 2000 - 2999.
I m Zero said:
1 decade ago
@Dechen.
Hi.
28th may 2006.
So we need to calculate form.
1 jan 0001st year to 28th may 2006th year.
First 1600th yr dont have odd days rite means 1600/4 = 0 odd day.
400/4 = 0 odd day.
So we reach 1st jan 2000th year ok. Now 2001, 2002,.... 2006 28th may.
Hi.
28th may 2006.
So we need to calculate form.
1 jan 0001st year to 28th may 2006th year.
First 1600th yr dont have odd days rite means 1600/4 = 0 odd day.
400/4 = 0 odd day.
So we reach 1st jan 2000th year ok. Now 2001, 2002,.... 2006 28th may.
Ambika said:
3 years ago
Day codes:
0 Sunday.
1 Monday.
2 Tuesday.
3 Wednesday.
4 Thursday.
5 Friday.
6 Saturday.
Month codes:
0 3 3 6 1 4 6 2 5 0 3 5
J F M A M J J A S O N D.
Day codes:
0 1 2 3 4 5 6
S M T W T F S
28 may 2006.
Add 28+06 = 34.
6÷4 =1 with two remainder.
34 + 1 = 35,
35/7=0 remainder.
0 = Sunday.
0 Sunday.
1 Monday.
2 Tuesday.
3 Wednesday.
4 Thursday.
5 Friday.
6 Saturday.
Month codes:
0 3 3 6 1 4 6 2 5 0 3 5
J F M A M J J A S O N D.
Day codes:
0 1 2 3 4 5 6
S M T W T F S
28 may 2006.
Add 28+06 = 34.
6÷4 =1 with two remainder.
34 + 1 = 35,
35/7=0 remainder.
0 = Sunday.
(58)
Rakhi said:
1 decade ago
It can be calculated in easier way:
2006 -> January - 31 = 31/7 = 3 odd days.
Feb- 28=28/7 = 0 odd days.
March - 31 =31/7 = 3 odd days.
April 30 = 30/7=2 odd days.
May up to 27 dayth : 27 / 7 =6 odd days.
Total: 3+0+3+2+6= 14 -> 14 /7 = 0 odd days.
0 i.e. Sunday.
Hence: answer = Sunday.
2006 -> January - 31 = 31/7 = 3 odd days.
Feb- 28=28/7 = 0 odd days.
March - 31 =31/7 = 3 odd days.
April 30 = 30/7=2 odd days.
May up to 27 dayth : 27 / 7 =6 odd days.
Total: 3+0+3+2+6= 14 -> 14 /7 = 0 odd days.
0 i.e. Sunday.
Hence: answer = Sunday.
Divya said:
1 decade ago
When we divide the number of days of a year with 7 it gives the number complete weeks in that year,and the reminder of this gives the number of days which are remaining in the year.these days are called as odd days (i.e.an incomplete week).
One year = number of complete weeks+number of odd days.
One year = number of complete weeks+number of odd days.
Shashank said:
1 decade ago
Guyz we always calculate from 31st DEC 200.. to 31 st DEC 200..
So here, 31 st DEC 2000 to 31st DEC 2005 we gonna calculate
Now year 2001, odd days => 1
2002 => 1
2003 => 1
2004 => 2
2005 => 1
6 odd days and rest of the calculation you can see above.
So here, 31 st DEC 2000 to 31st DEC 2005 we gonna calculate
Now year 2001, odd days => 1
2002 => 1
2003 => 1
2004 => 2
2005 => 1
6 odd days and rest of the calculation you can see above.
Shefali said:
9 years ago
No. Of odd day in 1600 is 0.
No. Of odd days in 400 is 0.
This is hypothetical for this kind of questions remember this. For 2000 and after use 400, for 1900 and for example 1998 or 1976 etc use 300, for 1800 and after ex 1889, 1887 or any year starting with 18 use 200 instead of 400.
No. Of odd days in 400 is 0.
This is hypothetical for this kind of questions remember this. For 2000 and after use 400, for 1900 and for example 1998 or 1976 etc use 300, for 1800 and after ex 1889, 1887 or any year starting with 18 use 200 instead of 400.
Ragi Akhil said:
1 decade ago
We have to calculate odd days till 2006 may 28. So it will be time taking process. So for simplifying the calculation process first we will find out the odd days till the year 2000. Odd days in 2000 years is 0. And after that we have to find out the odd days from 2001 to 2006 may 28.
Raghavendra naik said:
6 years ago
Since to know what is the day of 28th may.
2000year+5year+may 28.
100 year = 5odd days, 2000 year = 5 * 20 = 100days + 5 days(400,800,1200,1600,2000),
105days = 15 week 0 odd days,
5 years =1+1+1+2+1=6 odd days,
may 28 =1 odd day.
1+6=7 days=1 week 0 odd days.
So it's Sunday.
2000year+5year+may 28.
100 year = 5odd days, 2000 year = 5 * 20 = 100days + 5 days(400,800,1200,1600,2000),
105days = 15 week 0 odd days,
5 years =1+1+1+2+1=6 odd days,
may 28 =1 odd day.
1+6=7 days=1 week 0 odd days.
So it's Sunday.
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