Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 17 of 22.
Kasiraja said:
9 years ago
The January month has 31days in 4weeks, per week 7days. 31/7 then the remaining is 3. Therefore 3 is considered as odd days. 4weeks * 7days = 28. The remaining 3 is odd days.
Sathiyaraj said:
9 years ago
Assume, 01-01-01 be a Monday,
So, 2006/4 = 501 leap years + 2 days,
501/7 = 71 weeks + 4 days,
So, 31-12-2005 ends with Saturday (4 + 2 days = 6),
Hence, 01-01-2006 starts on Sunday,
Jan 31+ Feb 28 + Mar 31+ Apr 30 + May 28 = 148 days,
148/7 = 21 weeks + 1 days,
2005 ends on Saturday + 1 = Sunday,
So 28 May 2006 was Sunday.
So, 2006/4 = 501 leap years + 2 days,
501/7 = 71 weeks + 4 days,
So, 31-12-2005 ends with Saturday (4 + 2 days = 6),
Hence, 01-01-2006 starts on Sunday,
Jan 31+ Feb 28 + Mar 31+ Apr 30 + May 28 = 148 days,
148/7 = 21 weeks + 1 days,
2005 ends on Saturday + 1 = Sunday,
So 28 May 2006 was Sunday.
Salifu Adam w said:
9 years ago
Why 1600 is grouping first?
PRIYA said:
9 years ago
If we put 1990 instead of 1900 it will be right.
Jagath said:
9 years ago
MONTH CODE.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
YEAR CODE = 2006 - 6.
Sun = 1, Mon = 2, T = 3, W = 4, Thurs = 5, Fri = 6, Sat = 7 or 0.
28/5/2006.
D + M + Y + Leap year + Cc.
28 + 2 + 6 + 1 + 6 = 43.
43/7 = Q = 6, Re = 1.
J F M A M J J A S O N D
1 4 4 0 2 5 0 3 6 1 4 6
YEAR CODE = 2006 - 6.
Sun = 1, Mon = 2, T = 3, W = 4, Thurs = 5, Fri = 6, Sat = 7 or 0.
28/5/2006.
D + M + Y + Leap year + Cc.
28 + 2 + 6 + 1 + 6 = 43.
43/7 = Q = 6, Re = 1.
Hem said:
9 years ago
I want to know how many independents like Mondays in this century same as the days?
Could you please tell me and as the same of Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday?
Could you please tell me and as the same of Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday?
Bikramdevgan said:
9 years ago
Please memorise.
0 Jan
3 Feb
3 March
6 April
1 May
4 June
6 July
2 Aug
5 Sept
0 Oct
3 Nov
5 Dec
&
6 1600-1699
4 1700-1799
2 1800-1899
0 1900-2000
6 2000-2009
15 Aug 1947.
15 + 2 (month key) + 0(year key) + 47 + 11(47/4 "11" quotient) = 78.
78/7 remainder 1.
0 Sunday
1 Monday
2 Tuesday
3 Wednesday
4 Thursday
5 Friday
6 Saturday
Please tell me, If I am wrong.
0 Jan
3 Feb
3 March
6 April
1 May
4 June
6 July
2 Aug
5 Sept
0 Oct
3 Nov
5 Dec
&
6 1600-1699
4 1700-1799
2 1800-1899
0 1900-2000
6 2000-2009
15 Aug 1947.
15 + 2 (month key) + 0(year key) + 47 + 11(47/4 "11" quotient) = 78.
78/7 remainder 1.
0 Sunday
1 Monday
2 Tuesday
3 Wednesday
4 Thursday
5 Friday
6 Saturday
Please tell me, If I am wrong.
Kaybee said:
9 years ago
CAN YOU PLEASE HELP ME?
If I was born in 1984, no leap year and first day was Tuesday them how many Tuesdays are there in that year?
If I was born in 1984, no leap year and first day was Tuesday them how many Tuesdays are there in that year?
Hrithik said:
9 years ago
I'm not understanding the relation between 1600yrs & 400yrs.
Why not we can take 1200yrs & 800yrs instead of 1600yrs & 400yrs?
Why not we can take 1200yrs & 800yrs instead of 1600yrs & 400yrs?
Rajat Sharma said:
9 years ago
Because in 100 years there are (96/4) =24 leap years and other72 years are ordinary days and as.
100 years (76 ordinary years + 24 leap years).
= (76 x 1 + 24 x 2) odd days,
= 124 odd days.
= (17 weeks + 5 days) ,
= 5 odd days.
Hence the number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2) = 10 -> 3 odd days.
Number of odd days in 300 years = (5 x 3) = 15 -> 1 odd days.
Number of odd days in 400 years = (5 x 4 + 1) = 21 -> 0 odd days.
Similarly, the number of odd days in all 4th centuries (400, 800, 1200 etc. ) = 0.
That is why we take 1600 & 400 instead of 1200, 800 etc. Numbers.
100 years (76 ordinary years + 24 leap years).
= (76 x 1 + 24 x 2) odd days,
= 124 odd days.
= (17 weeks + 5 days) ,
= 5 odd days.
Hence the number of odd days in 100 years = 5.
Number of odd days in 200 years = (5 x 2) = 10 -> 3 odd days.
Number of odd days in 300 years = (5 x 3) = 15 -> 1 odd days.
Number of odd days in 400 years = (5 x 4 + 1) = 21 -> 0 odd days.
Similarly, the number of odd days in all 4th centuries (400, 800, 1200 etc. ) = 0.
That is why we take 1600 & 400 instead of 1200, 800 etc. Numbers.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers