Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 17 of 22.
Gani said:
1 decade ago
@Deena
I got the solution for this type of problem
Thanks for the useful formula.
I got the solution for this type of problem
Thanks for the useful formula.
Sindhu said:
1 decade ago
How we can take jan-1, feb-4...
Rekha said:
1 decade ago
Can you please explain brief?
Dipika said:
1 decade ago
@Deena
How you take 2006-1900=16? Its 106.
How you take 2006-1900=16? Its 106.
Subin said:
1 decade ago
Why chosen 2001-2005 please explain as soon as possible ?
Vijay singh said:
1 decade ago
Dont know how 1600 and 400 have been accounted.
Number of leap yrs in 2000 yrs= 2000/4-15=485 yrs
(4 is included because leap year comes generally once in 4 yrs.
15 is subtracted because some of yrs namely 100,200,300,500,600 700,900,1000,1100,1300,1400,1500,1700,1800,1900 are not leap yrs in 2000 yrs)
Number of odd days in leap yrs= Remainder of 485*2/7 = 4 days
Number of non leap yrs in 2000 yrs= 2000-485 = 1515 yrs
Number of odd days in non leap yrs= Remainder of 1515/7 = 3 Days
Therefore number of odd days in 2000 yrs= Remainder of(4+3)/7= 0
And for next five yrs from 2001 to 2005 and onwards it is been described in solution.
Number of leap yrs in 2000 yrs= 2000/4-15=485 yrs
(4 is included because leap year comes generally once in 4 yrs.
15 is subtracted because some of yrs namely 100,200,300,500,600 700,900,1000,1100,1300,1400,1500,1700,1800,1900 are not leap yrs in 2000 yrs)
Number of odd days in leap yrs= Remainder of 485*2/7 = 4 days
Number of non leap yrs in 2000 yrs= 2000-485 = 1515 yrs
Number of odd days in non leap yrs= Remainder of 1515/7 = 3 Days
Therefore number of odd days in 2000 yrs= Remainder of(4+3)/7= 0
And for next five yrs from 2001 to 2005 and onwards it is been described in solution.
Arpit said:
1 decade ago
@NAVEEN. Thanks. !
Ajay said:
1 decade ago
Deena's solution is correct just take 106 instead of 16 106/4 you will get quotient 26 and remainder 2 leave the remainder and take 26 you will get the right answer.
Meenu said:
1 decade ago
Hi All,
Deena s solution is correct. Its 106 not 16... But try to substitute 106 instead of 16.. We are getting the same answer. I tried with some other questions also,its working.. Good Solution Deena.... Thanks :-)
Deena s solution is correct. Its 106 not 16... But try to substitute 106 instead of 16.. We are getting the same answer. I tried with some other questions also,its working.. Good Solution Deena.... Thanks :-)
Satish mohan said:
1 decade ago
Hi Naveen thank you for your information.
Your method is good I like this method.
Please tell me how to know this method and give me some ideas.
Your method is good I like this method.
Please tell me how to know this method and give me some ideas.
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