Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 2)
2.
What was the day of the week on 28th May, 2006?
Answer: Option
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 
6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
Discussion:
214 comments Page 16 of 22.
Asa said:
1 decade ago
Solution: JFM AMJ JAS OND
1. Choose appropriate month code: 602 503 514 624
2. Leap years since 1/1/2000 (including the year 2000):
3. Add the month code from step 1, the number of leap years, the day of the month, and the amt of years since 2000. Divide this by 7 and take the remainder.
4. Sun = 1, Mon= 2, T = 3...Fri=6, Sat=0,7
Example: January 1,2050
1. month code 6 2. 50yrs/4=12r2. 12+1 (since Feb 2000 had a leap day) = 13
3. 6 + 13 + 1 + 50 = 70. 70/7=10r0
4. remainder of 0 -> January 1, 2050 will be a Saturday
*If the year you are calculating is a leap year and the date is BEFORE February 29, do add the 1*
Example of this: February 18, 2008
1. month code 2
2. 2 (Feb 2000 & 2004 BUT NOT 2008 yet)
3. 2 + 2 + 18 + 8 = 30. 30/7=4r2
4. remainder 2 -> Monday
1. Choose appropriate month code: 602 503 514 624
2. Leap years since 1/1/2000 (including the year 2000):
3. Add the month code from step 1, the number of leap years, the day of the month, and the amt of years since 2000. Divide this by 7 and take the remainder.
4. Sun = 1, Mon= 2, T = 3...Fri=6, Sat=0,7
Example: January 1,2050
1. month code 6 2. 50yrs/4=12r2. 12+1 (since Feb 2000 had a leap day) = 13
3. 6 + 13 + 1 + 50 = 70. 70/7=10r0
4. remainder of 0 -> January 1, 2050 will be a Saturday
*If the year you are calculating is a leap year and the date is BEFORE February 29, do add the 1*
Example of this: February 18, 2008
1. month code 2
2. 2 (Feb 2000 & 2004 BUT NOT 2008 yet)
3. 2 + 2 + 18 + 8 = 30. 30/7=4r2
4. remainder 2 -> Monday
Lalitha said:
1 decade ago
How can we say the odd day is 0 for 1600 and 400 years...i am getting 1 odd day for total 2000 years....hear is my calculation if wrong pls corret it..
2000/4=500
so 500 leap years..no of odd days for 500 years is (500*2)1000
and 1500 ordinary years having 1500 odd days
total=1500+1000=2500
no of odd days in these 2500 days: 2500/7 = 1 odd day
is it correct procedure?
2000/4=500
so 500 leap years..no of odd days for 500 years is (500*2)1000
and 1500 ordinary years having 1500 odd days
total=1500+1000=2500
no of odd days in these 2500 days: 2500/7 = 1 odd day
is it correct procedure?
Madhu said:
1 decade ago
How can we say 0 is sunday 1 is monday, 2 tues day, . How can we know the jan 1st 2006 week day?
Rabin said:
1 decade ago
Why there is 1900 in above mentioned explanation?
Rakhi said:
1 decade ago
I can't understand this step plz explain it?? 5=(5/4)leap yr+[5-1]ordinary day
=1 leap year+4 ordinary day
=1 leap year+4 ordinary day
Rakhi said:
1 decade ago
It can be calculated in easier way:
2006 -> January - 31 = 31/7 = 3 odd days.
Feb- 28=28/7 = 0 odd days.
March - 31 =31/7 = 3 odd days.
April 30 = 30/7=2 odd days.
May up to 27 dayth : 27 / 7 =6 odd days.
Total: 3+0+3+2+6= 14 -> 14 /7 = 0 odd days.
0 i.e. Sunday.
Hence: answer = Sunday.
2006 -> January - 31 = 31/7 = 3 odd days.
Feb- 28=28/7 = 0 odd days.
March - 31 =31/7 = 3 odd days.
April 30 = 30/7=2 odd days.
May up to 27 dayth : 27 / 7 =6 odd days.
Total: 3+0+3+2+6= 14 -> 14 /7 = 0 odd days.
0 i.e. Sunday.
Hence: answer = Sunday.
Ravindra reedy said:
1 decade ago
Suppose we have 23days at this time find odd days?
Ans:
No of days is divisible by 7 then we get odd days.
23/7=2.
2 odd days.
Ans:
No of days is divisible by 7 then we get odd days.
23/7=2.
2 odd days.
Chirag said:
1 decade ago
Rule 1: Find the remind from complete years by dividing 28
i.e(2005/28 gives 17)
So consider 17 years as left.. it has 4 leap year
as general procedure code for that is 0
Rule 2: Same for month and date calculation :
(31+28+31+30+28)/7 it gives remainder 1
So code is 1
Total code is 1+0=1
Now,
MAGIC rule: add 6 in total cade
i.e (1+6=7)
So code is 7 means 0 means Sunday ! !
It can apply for any type of question...
i.e(2005/28 gives 17)
So consider 17 years as left.. it has 4 leap year
as general procedure code for that is 0
Rule 2: Same for month and date calculation :
(31+28+31+30+28)/7 it gives remainder 1
So code is 1
Total code is 1+0=1
Now,
MAGIC rule: add 6 in total cade
i.e (1+6=7)
So code is 7 means 0 means Sunday ! !
It can apply for any type of question...
Shawisk said:
1 decade ago
@Deena.
What we write instead for 1900 if the date is 13 may 1666
For = 28+2+(2006-1900)+(2006-1900)/4.
What we write instead for 1900 if the date is 13 may 1666
For = 28+2+(2006-1900)+(2006-1900)/4.
Jyothi said:
1 decade ago
@Deena.
How you got 2006-1900= 16 please explain.
How you got 2006-1900= 16 please explain.
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