Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 7 of 17.
Harish said:
1 decade ago
Solution:
First we calculate upto 1997.
1998 = 1600+300+97.
For 1600 0odd days because 1600 is divisible by 4 so it is 0.
For 300 is 1 odd days.
For 97 we have 24 leap year and 73 ordinary year.
Calculate if leap year*2 so 24*2 = 48+73.
=121.
While dividing 121 by 7 we get remainder as 2 that is 2 odd days.
Still we have to calculate from jan 1998 to 17th june 1998 we have 168 days if We divided by 7 remainder is zero.
Totally we have 3 odd days.
Sun Mon Tue Wed Thu Fri Sat
0 1 2 3 4 5 6
So answer is wed.
First we calculate upto 1997.
1998 = 1600+300+97.
For 1600 0odd days because 1600 is divisible by 4 so it is 0.
For 300 is 1 odd days.
For 97 we have 24 leap year and 73 ordinary year.
Calculate if leap year*2 so 24*2 = 48+73.
=121.
While dividing 121 by 7 we get remainder as 2 that is 2 odd days.
Still we have to calculate from jan 1998 to 17th june 1998 we have 168 days if We divided by 7 remainder is zero.
Totally we have 3 odd days.
Sun Mon Tue Wed Thu Fri Sat
0 1 2 3 4 5 6
So answer is wed.
Dharsinipriya said:
1 decade ago
How to calculate leap year and ordinary year between 200 years?
Pragati said:
1 decade ago
First divide that no by 4.
200/4 = 50 is the leap year.
And 200-50 = 150 is the ordinary year.
200/4 = 50 is the leap year.
And 200-50 = 150 is the ordinary year.
Vinod zala said:
1 decade ago
Friends it's so simple, Remember only code:
Year Code:
1600-1699 = 6.
1700-1799 = 4.
1800-1899 = 2.
1900-1999 = 0.
2000-2099 = 6.
Month Code:
Jan = 0
Feb = 3
Mar = 3
April = 6
May = 1
June = 4
July = 6
Aug = 2
Sep = 5
Oct = 0
Nov = 3
Dec = 5
Day Code:
Sunday = 0
Monday = 1
Tuesday = 2
Wednesday = 3
Thursday = 4
Friday = 5
Saturday = 6
Steps to solve:
What was day on 17/8/1998 ?
Step:1 (add day + last two digit of years).
(17+98=115).
Step:2 (divide last two digit of years by 4).
98/4 == 24.
Step:3 (add code value)
115
+24
+04 --- month code.
+00 --- year code.
-----
143.
Step: 4 (divide result step 3 by 7).
143/7 = 3.
Step:5 (match with day code).
3 === Wednesday.
Year Code:
1600-1699 = 6.
1700-1799 = 4.
1800-1899 = 2.
1900-1999 = 0.
2000-2099 = 6.
Month Code:
Jan = 0
Feb = 3
Mar = 3
April = 6
May = 1
June = 4
July = 6
Aug = 2
Sep = 5
Oct = 0
Nov = 3
Dec = 5
Day Code:
Sunday = 0
Monday = 1
Tuesday = 2
Wednesday = 3
Thursday = 4
Friday = 5
Saturday = 6
Steps to solve:
What was day on 17/8/1998 ?
Step:1 (add day + last two digit of years).
(17+98=115).
Step:2 (divide last two digit of years by 4).
98/4 == 24.
Step:3 (add code value)
115
+24
+04 --- month code.
+00 --- year code.
-----
143.
Step: 4 (divide result step 3 by 7).
143/7 = 3.
Step:5 (match with day code).
3 === Wednesday.
Sahithi said:
1 decade ago
Please any one explain how to find 11th oct 1993 - day?
But above explained rules are not giving exact day what it is.
But above explained rules are not giving exact day what it is.
Deepak said:
1 decade ago
How to calculate odd day in 1600 years?
MaheshMydo said:
1 decade ago
How did you arrive at MONTH CODES?
Prince said:
1 decade ago
We can solve this problem by going back from 2000 to 17 June 1998.
= 2000-2 odd days (leap year).
= 1999-1 odd day.
= 1988 (197 days i.e 1 odd day) (31 dec+30 nov. 17 june).
Total 4 odd days.
Since we have reversely calculated it.
Sat, Fri, Thurs, Wed.
= 2000-2 odd days (leap year).
= 1999-1 odd day.
= 1988 (197 days i.e 1 odd day) (31 dec+30 nov. 17 june).
Total 4 odd days.
Since we have reversely calculated it.
Sat, Fri, Thurs, Wed.
John said:
1 decade ago
@Mickey.
Now divide 144 by 7.
We'll get quotient = 20 and remainder = 4.
So 4th day is Wednesday.
Here remainder is wrong. We will get it as 5.
How you get remainder as 4?
Now divide 144 by 7.
We'll get quotient = 20 and remainder = 4.
So 4th day is Wednesday.
Here remainder is wrong. We will get it as 5.
How you get remainder as 4?
Monu said:
1 decade ago
If 15 august 1993 is Friday then what would be the day of 6th march of same year? Anybody please answer this.
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