Aptitude - Calendar - Discussion
Discussion Forum : Calendar - General Questions (Q.No. 3)
3.
What was the day of the week on 17th June, 1998?
Answer: Option
Explanation:
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) 
1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
Discussion:
165 comments Page 4 of 17.
Vanita said:
1 decade ago
Number of odd days in 200 years = (5 x 2) 3 odd days.
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
Why, (Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.) in this 1 is added ,
please clarify
Number of odd days in 300 years = (5 x 3) 1 odd day.
Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.
Why, (Number of odd days in 400 years = (5 x 4 + 1) 0 odd day.) in this 1 is added ,
please clarify
Goms said:
1 decade ago
The basic rule to know about leap year is that the year should be divisible by 4.
For Eg: 4, 8, 12, 16, 20................100, 104 etc.,
Then here as per my knowledged 25 leap years should exists for every 100 years.
why all are considering 24 yrs in 100 years?
For Eg: 4, 8, 12, 16, 20................100, 104 etc.,
Then here as per my knowledged 25 leap years should exists for every 100 years.
why all are considering 24 yrs in 100 years?
Suraj Singh said:
10 years ago
Before asking questions, you guys should have clear concept on leap year.
A leap year is a year, which is divisible by 400, or which is divisible by 4 and not divisible by 100.
So 100, 200, 300 is not a leap year.
So in 100 years, only 24 leap years, and so on.
A leap year is a year, which is divisible by 400, or which is divisible by 4 and not divisible by 100.
So 100, 200, 300 is not a leap year.
So in 100 years, only 24 leap years, and so on.
Prince said:
1 decade ago
We can solve this problem by going back from 2000 to 17 June 1998.
= 2000-2 odd days (leap year).
= 1999-1 odd day.
= 1988 (197 days i.e 1 odd day) (31 dec+30 nov. 17 june).
Total 4 odd days.
Since we have reversely calculated it.
Sat, Fri, Thurs, Wed.
= 2000-2 odd days (leap year).
= 1999-1 odd day.
= 1988 (197 days i.e 1 odd day) (31 dec+30 nov. 17 june).
Total 4 odd days.
Since we have reversely calculated it.
Sat, Fri, Thurs, Wed.
Priyanka Agrawal said:
9 years ago
@ Bidhya.
When no.of days are divided by 7 we get reminder, the reminder is called odd days.
Eg. In one year [non-leap year] there are 365 days,
So 365/7 = 1[reminder].
Then there is 1 Odd day in one year.
Simply no.of days/7 = reminder means odd days.
When no.of days are divided by 7 we get reminder, the reminder is called odd days.
Eg. In one year [non-leap year] there are 365 days,
So 365/7 = 1[reminder].
Then there is 1 Odd day in one year.
Simply no.of days/7 = reminder means odd days.
Pratyush Singh said:
4 years ago
96/4 = 24. and 96 -24 =72 ordinary years.
This means in 96 years there are 24 leap years and 72 ordinary years.
So, in 97 years = 96 (24 odd +72 ordinary)+ 1 (ordinary).
=> 97 years = 24 odd + 73 ordinary years.
i.e. 97-24 = 73 ordinary years.
This means in 96 years there are 24 leap years and 72 ordinary years.
So, in 97 years = 96 (24 odd +72 ordinary)+ 1 (ordinary).
=> 97 years = 24 odd + 73 ordinary years.
i.e. 97-24 = 73 ordinary years.
(4)
Yadagiri said:
2 years ago
The last digit of the year = 98.
Quotient when divisible by 4 = 24.
Day in the given date = 17.
Digit of the month = 4.
Digit of the year = 0.
Add all these you will get = 143*7.
You will get the remainder as 3.
Then the above day is Wednesday.
Quotient when divisible by 4 = 24.
Day in the given date = 17.
Digit of the month = 4.
Digit of the year = 0.
Add all these you will get = 143*7.
You will get the remainder as 3.
Then the above day is Wednesday.
(36)
Abhi said:
8 years ago
One other way of Finding the Answer is :
Just remember that 1st Jan 2000 was Saturday.
1999 (not leap year so 365 days) = 52 weeks + 1 day.
So to go to 1st Jan 1999 just have to subtract that 1 Extra day which is bringing the change.
Just remember that 1st Jan 2000 was Saturday.
1999 (not leap year so 365 days) = 52 weeks + 1 day.
So to go to 1st Jan 1999 just have to subtract that 1 Extra day which is bringing the change.
Sathiyaraj said:
9 years ago
1998/4 = 499 leap years + 2 days,
499/7 = 71 weeks + 2 days,
So, 01-01-1998 falls on Wednesday(4th day of week),
Jan 31 + Feb 28 + Mar 31 + Apr 30 + May 31 + Jun 17 = 168 /7 = 24 weeks + 0 day,
So, 17 jun 1998 falls on Wednesday.
499/7 = 71 weeks + 2 days,
So, 01-01-1998 falls on Wednesday(4th day of week),
Jan 31 + Feb 28 + Mar 31 + Apr 30 + May 31 + Jun 17 = 168 /7 = 24 weeks + 0 day,
So, 17 jun 1998 falls on Wednesday.
R G said:
6 years ago
Here, for calculation of 1997, they have said 1600 yrs + 300 yrs.
So the odd day obtained is 1. But instead, if we do 1700 yrs + 200 yrs than odd days obtained will be different. How to understand this? Please explain to me.
So the odd day obtained is 1. But instead, if we do 1700 yrs + 200 yrs than odd days obtained will be different. How to understand this? Please explain to me.
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